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antoniya [11.8K]
3 years ago
12

Which equation is correct

Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
7 0
1. Two of the main identities used in trigonometry for right triangles (Triangles that have an angle of 90°) are: Sine (Sin) and Cosine (Cos).


 Sin x°=Opposite/Hypotenuse

 Cos x°=Adjacent/Hypotenuse

 2. The inverse of Sinx° is Cosec x°, then:

 Cosec x°=1/Sin x°

 3. The inverse of Cos x° is Sec x°, then:

 Sec x°=1/Cos x°

 4. Keeping this on mind, you have:

 Cosc x°=Hypotenuse/Opposite

 Sec x°=Hypotenuse/Adjacent

 5. Therefore, the correct answer is:

 The third option: Cosec x°=Hypotenuse/Opposite.
Murljashka [212]3 years ago
3 0

Answer:

c

Step-by-step explanation:

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D.A plane consist of an infinite set of lines.
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Conduct the appropriate hypothesis test and compute the test statistic. A company that produces fishing line undergoes random te
andre [41]

Answer:

Option D) Yes, because the test statistic is -2.01

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 30 pound

Sample mean, \bar{x} = 29.1 pounds

Sample size, n = 20

Alpha, α = 0.05

Sample standard deviation, s =  2 pounds

First, we design the null and the alternate hypothesis

H_{0}: \mu = 30\text{ pounds}\\H_A: \mu < 30\text{ pounds}

We use one-tailed(left) t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{29.1 - 30}{\frac{2}{\sqrt{20}} } = -2.012

Now,

t_{critical} \text{ at 0.05 level of significance, 19 degree of freedom } = -1.729

Since,                    

t_{stat} < t_{critical}

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis. Thus, there were enough evidence to conclude that the fishing line breaks with an average force of less than 30 pounds.

Option D) Yes, because the test statistic is -2.01

5 0
3 years ago
Which of the following transforms this non-statistical question into a statistical question? How much food does your dog eat?
kozerog [31]

Answer:

A) Not statistical /this question is answered by counting the number of days in March. This produces a single number. This number is not answered by collecting data that vary.

B) Not Statistical/ this question is answered by a single number. It is not answered by collecting data that vary.

C) Statistical/ this question would be answered by all collecting data, and there would be variability in that data.

D) statistical/ this question would be answered by collecting data, and there would be variability in that data

E) Not Statistical/ this question is answered by a single response. It is not answered by collecting data that vary.

F) not statistical/ this question would be answered by counting the bricks. This produces a single number. This question is not answered by collecting data that very

G) non-statistical/ there is only one temperature

4 0
2 years ago
Read 2 more answers
A strobe light is located at the center of a square dance room. the rotating light is 40 feet from each of the square walls and
Effectus [21]

The equation of the rotating light is an illustration of a secant function

The equation that represents the distance between the center of the circle and the light source is d(t) = 40\sec(\frac{\pi}{3}t)

<h3>How to determine the equation</h3>

The equation is a secant function represented by

y =A\sec(Bt)

Where:

A represents the amplitude

So, we have:

A = 40 --- the distance of the light from each square wall

B represents the period, and it is calculated as:

B = \frac{2\pi}{T}

The light completes its full rotation every 6 seconds.

This means that,

T = 6

So, we have:

B = \frac{2\pi}{6}

Simplify

B = \frac{\pi}{3}

Substitute values for A and B in y =A\sec(Bt)

y = 40\sec(\frac{\pi}{3}t)

Rewrite as a function

d(t) = 40\sec(\frac{\pi}{3}t)

Hence, the equation that represents the distance between the center of the circle and the light source is d(t) = 40\sec(\frac{\pi}{3}t)

Read more about trigonometry functions at:

brainly.com/question/1143565

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2 years ago
Evaluate 2(x+4)^2 - (3y+5)^3 for x= -3 and y= -1
UNO [17]
<span>2(x+4)^2 - (3y+5)^3
at x=-3 and y=-1

2(-3+4)^2 - ((3*-1)+5)^3
2 (1)^2 - (2)^3
2 - 8
(-6)</span>
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3 years ago
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