N is equal to 2.5
I divided 20 by 5 to get 4. = 20 ÷ 5 = 4. So, I divide 10 by 4 to get n. = 10 ÷ 4 = 2.5
Or we can do this solution.
20 5
---- = ---- ; do cross multiplication. 20n = 10(5)
10 n
20n = 50 ; to get n, divide both sides by 20. 20n / 20 = 50 / 20 = n = 2.50
Whichever way: 20/10 = 5/2.5
Answer:
The probability is 2.2%
Step-by-step explanation:
The probability that a randomly selected adult uses the telephone in classes is always equal to 0.48.
If x represents the number of adults selected from among the 8 that the telephone uses in classes, then x is a discrete random variable that follows a binomial distribution, with:
p = 0.48
q = 0.52
n = 8
We want to find the probability of x = 5

The probability is 2.2%
Answer:
Sin of x does not change
Step-by-step explanation:
Whenever a triangle is dilated, the angle remains the same as well as the ratio for sides of triangle. For smshapes with dimensions, when shapes are dilated the dimensions has increment with common factor.
From trigonometry,
Sin(x)=opposite/hypotenose
Where x=4/5
Sin(4/5)= opposite/hypotenose
But we were given the scale factor of 2 which means the dilation is to two times big.
Then we have
Sin(x)=(2×opposite)/(2×hypotenose)
Then,if we divide by 2 the numerator and denominator we still have
Sin(x)=opposite/hypotenose
Which means the two in numerator and denominator is cancelled out.
Then we still have the same sin of x. as sin(4/5)
Hence,Sin of x does not change
Answer:
can you take a better pick
Step-by-step explanation:
Answer:
d.
Step-by-step explanation:
if x varies directly as y,
x = ky
8 = 12k
12k = 8
k = 8/ 12
k = 2/3,
x = 2/3 y
now substitute the value of any of the numbers of each pair, and check if it works:
for e.g, find x when y = 15
x = 2/3y
x = 2/3 × 15
x = 10
since you obtain x = 10 when y = 15, the pair is a possible corresponding value of x and y. now do the same for the rest .
ii) x = 2/3y
x = 2/3 × 3, when y = 3
x = 2
hence, this is also a possible pair of x and y values.
iii) x = 2/3y
x = 2/3 × 9 when y = 9
x = 6
again, a possible pair of x and y values.
iv) x = 2/3y
x = 2/3 × 20 when y = 20
x = 40/3
here, when y = 20, x is not 15. it is 40/3.
thus, it can be determined that this is not a possible pair of x and y values.
please try to understand and have a great day!