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I think this is the answer.
Hope this helps!
Answer:
The margin of error that corresponds to a 95% confidence interval is 4.96.
Step-by-step explanation:
We have the standard error(which is the same as the standard deviation of the sample), so we use the students t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. There are 6 days, so
df = 6 - 1 = 5
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of
). So we have T = 2.5706
The margin of error is:
M = T*s = 2.5706*1.93 = 4.96
The margin of error that corresponds to a 95% confidence interval is 4.96.
Answer:
it could be the number in 2015 is 2,330
Step-by-step explanation:
Just add the number of the students in 2014-2016.
1,030+ 1,300=2,330
Ummm I don’t find a way to give this a response, but the Best Buy it would be snack packs because he’s getting a finance