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3 years ago

The variables y and x have a proportional relationship, and y = 24 when x = 16.

Mathematics

2 answers:

Goryan [66]3 years ago

7 0

Answer:

x=24 or B is the correct answer.

I took the test, and this was the correct answer. Hope this helped-!

frosja888 [35]3 years ago

3 0

Answer:

b) x = 24

Step-by-step explanation:

if y is 24 and x is 16, they make the fraction $\frac{24}{16}$

this can be simplified to $\frac{3}{2}$ if you divide both sides of the fraction by 8.

36/3 is 12, and 12 * 2 = 24.

so, x = 24

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10 - 5 2/3 = ? not in decimal form only fraction .

Dmitrij [34]

it would equal the same mixed number. 5 2/3

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3 years ago

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HELP WITH THIS QUESTION PLEASE!!

svetlana [45]

m<PQS = m<SQR

4y - 10 = 2y + 10

2y = 20

y = 10

m<PQR = m<PQS + m<SQR

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= 6y

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3 years ago

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egoroff_w [7]

The correct answer is:
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4 years ago

A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f

Andrews [41]

Answer:

$A = \frac{P}{r}\left( e^{rt} -1 \right)$

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

$\frac{dA}{rA+P} = dt$

Integration on both sides gives

$\int \frac{dA}{rA+P} = \int dt$

where $c$ is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

$\int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c$