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jonny [76]
4 years ago
8

Is the square root of infinity still infinity?.

Mathematics
1 answer:
hram777 [196]4 years ago
6 0
The square root of infinity is still infinity, or rather, undefined or indeterminate. For example, if you take the square root of a big number, you will still have a big number as a result, now if you make the number even bigger, the square root will also get bigger, now imagine what will happen if this number is infinite.
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What equation is equivalent to x^4-12x^2+36
vredina [299]
Simply solve the square.

(X^2-6)^2
7 0
4 years ago
Need help with #5.<br> Find angle and solve for x
Leona [35]

Answer:

see explanation

Step-by-step explanation:

The 2 marked angles are vertical and congruent, thus

24x = 23x + 5 ( subtract 23x from both sides )

x = 5

Thus angles = 24 × 5 = 120°

6 0
3 years ago
Mr Huey gas 54 sheets of paper he gave each boy 9 sheets.how many boys are there
emmainna [20.7K]

Answer:

There are six boys

Step-by-step explanation:

Divide 54 sheets by number of boys (9)

4 0
3 years ago
Read 2 more answers
Can someone help me?
frutty [35]
To multiply a fraction with another fraction, we multiply the numerators the denominators:

(5/2) x (2/3) = (5 x 2) / (6 x 3) = 10/18 = 5/9 
8 0
3 years ago
An automobile manufacturer has discovered that 20% of all the transmissions it installed in a particular style of truck are defe
Hatshy [7]

Answer:

0.148 = 14.8% probability that they will need to order at least one more new transmission

Step-by-step explanation:

For each transmission, there are only two possible outcomes. Either it is defective after a year of use, or it is not. The probability of a transmission being defective is independent of any other transmission. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

20% of all the transmissions it installed in a particular style of truck are defective after a year of use.

This means that p = 0.2

Sold seven trucks:

This means that n = 7

It has two of the new transmissions in stock. What is the probability that they will need to order at least one more new transmission?

This is the probability that at least 3 are defective, that is:

P(X \geq 3) = 1 - P(X < 3)

In which

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{7,0}.(0.2)^{0}.(0.8)^{7} = 0.2097

P(X = 1) = C_{7,1}.(0.2)^{1}.(0.8)^{6} = 0.3670

P(X = 2) = C_{7,2}.(0.2)^{2}.(0.8)^{5} = 0.2753

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2097 + 0.3670 + 0.2753 = 0.852

P(X \geq 3) = 1 - P(X < 3) = 1 - 0.852 = 0.148

0.148 = 14.8% probability that they will need to order at least one more new transmission

6 0
3 years ago
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