Can a Scalene triangle be a isosceles triangle? A: Always B: Never C: Sometimes

1 answer:

3 0

A scalene triangle can never be an isosceles triangle. How? Well, let's take a look at the definition of a scalene triangle. In short, a scalene triangle is a classification of a triangle that does not have any congruent sides. On the other hand, an isosceles triangle is a triangle in which its legs are both congruent. Therefore, if a scalene triangle has two congruent legs, it wouldn't even be a scalene triangle, but instead it would be an isosceles triangle. Hope this helped!

You might be interested in

The graph of the function f(x) = –(x + 3)(x – 1) Which statement about the function is true

Alex73 [517]

I think the answer is 2.The function is negative for all real values of x where x < –3 and where x > 1.

7 0

3 years ago

At a local event, the ratio of hamburgers to hot dogs sold is 5:3. The number of hamburgers sold is 275. How many more hamburger

sveticcg [70]

*your
If the ratio is 5:3, then you divide 275 by 5, and then multiply it by 3. If you test the result, you'll find that the ratio fits.

4 0

2 years ago

Two step educations 3c - 6 = 12

N76 [4]

Answer:

C = 6

Step-by-step explanation:

Move all terms that don't contain C to the right side and solve.

5 0

2 years ago

Read 2 more answers

Which function families have vertical symmetry?

Nady [450]

The functions which are even are symmetric to y-axis. By even functions, it means that f(x) = f(x) for all the domain values. Thus even functions for example, x^2, 1+x^2, cosx, x^4 all follow the conditions i.e. f(x) = f(x) and thus they are symmterical to y-axis.

8 0

2 years ago

Find the equation of this line (-3,0) (0 1)

NikAS [45]

$\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-0}{0-(-3)}\implies \cfrac{1}{0+3}\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=\cfrac{1}{3}[x-(-3)] \\\\\\ y=\cfrac{1}{3}(x+3)\implies y=\cfrac{1}{3}x+1$

3 0

2 years ago