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maw [93]
3 years ago
15

What is 2 3/2 equal to?

Mathematics
1 answer:
Setler79 [48]3 years ago
6 0

For this case we have the following expression:

2 ^ {\frac {3} {2}}

We must indicate an equivalent expression. By definition of properties of powers and roots we have:

\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}

Then, rewriting the expression:2 ^ {\frac {3} {2}} = \sqrt {2 ^ 3} = \sqrt {8}

Then, the expression is equivalent to the square root of 8.

ANswer:

Square root of 8.

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Monica plans to buy markers and colored pencils at an office supply store A box of markers cost $3.85 and a a box of colored pen
serg [7]

Answer:

Step-by-step explanation:

m=7

c=5

balance=26.802

8 0
3 years ago
-6(y + 15) = -3y + 6 what is the value of y
Serga [27]

Let's begin by listing out the information given to us:

-6\mleft(y+15\mright)=-3y+6

We are to find the value of y

undefined

6 0
1 year ago
Anyone know the answer to all of them added together
Evgesh-ka [11]

Answer:

13x + 14

Step-by-step explanation:

5x + 6 + 3x = 8x + 6.

8x + 6 + x + 1 + x + 1 + 2= 10x + 10

10x + 10 + (2²)(i think) = 10x + 14

10x + 14 + 3x = 13x + 14

final answer

3 0
3 years ago
Read 2 more answers
The second term of a GP is 4, the fifth term is 81. Find the seventh term
navik [9.2K]

Answer:

The seventh term of a G.P is

t_{7}  = 33,097.211

Step-by-step explanation:

<u><em>step(i):</em></u><em>-</em>

<em>Given the second term of a G.P is '4'</em>

<em>The general term of nth term is </em>

<em></em>t_{n}  = ar^{n-1}<em></em>

<em></em>t_{4}  = ar^{4-1} =4  

ar^{3} =4 …(i)    

<em>Also Given the fifth term of a G.P is '81'</em>

t_{5}  = ar^{5-1} =81

ar^{4} =81  …(ii)      

<u><em>Step(ii)</em></u>:-

<em>Dividing the equation (ii) divided by (i)</em>

<em />\frac{ar^{4} }{ar^{3} } = \frac{81}{4}<em />

<em>cancellation ' a' and 'r' terms , we get</em>

<em />r = \frac{81}{4}=20.25<em />

<em>substituting 'r' Value in equation (i), we get</em>

<em></em>ar^{3} =4<em></em>

a(\frac{81}{4}) ^{3} =4  

a = \frac{4X4X4X4}{(81)^{3} }= \frac{256}{531,441}

a = 0.00048

<u><em>Step(iii):-</em></u>

<u><em>The seventh term of G.P </em></u>

<em>The general term of nth term is </em>

<em></em>t_{n}  = ar^{n-1}<em></em>

<em></em>t_{7}  = (0.00048)(20.25)^{7-1}<em></em>

<em></em>t_{7}  = (0.00048)(20.25)^{6}= 33,097.211<em></em>

<em></em>

<em></em>

3 0
4 years ago
PLZ HELP
Roman55 [17]
She has 65 water bottles....and she is buying boxes of water bottles (x) that hold 16 water bottles each. She can only buy up to 5 water bottles.

f(x) = 16x + 65...where f(x) = total water bottles and x = number of boxes
x < = 5.....here is ur restriction

the range is ur f(x) values which represent the total number of water bottles...keep in mind, she can only buy 5. Therefore, the numbers that can be subbing in for x are 0 thru 5.

So when subbing in 0 thru 5 for x, the results for f(x) are :
{ 65,81,97,113,129 } <== ur range
4 0
4 years ago
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