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2 years ago

6

Monica plans to buy markers and colored pencils at an office supply store A box of markers cost $3.85 and a a box of colored pen

cils cost $1.85. She has $40 to spend Which inequality best represents how many boxes of markers m and colored pencils c she can buy

1 answer:

serg [7]2 years ago

8 0

Answer:

Step-by-step explanation:

m=7

c=5

balance=26.802

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Which of the following pairs of numbers contain like fractions?

saveliy_v [14]

Like fractions are fractions that have the same denominator. In option D, both denominators are 7. Therefore, they are like fractions.

7 0

3 years ago

Read 2 more answers

When three times the sum of a number and seven is increased by ten, the result is four. What is the number ?

densk [106]

Answer:

x=9 :))

Step-by-step explanation:

First set up your equation.

"3 times" is multiplication

"THE SUM of A NUMBER and seven" that is parenthesis because of the multiplication before it

"is increased by ten" that is an addition at the end

Now we have 3(x+7)+10=4

Solve your equation!

Distribute the 3 now we have 3x+21+10=4

Add like terms

now it should look like this... 3x+31=4

Subtract 31 from both sides and it looks like...

3x=27

Divide by the x-value

x=9

4 0

3 years ago

AlekseyPX

Answer:

D.

Step-by-step explanation:

Find the average rate of change of each given function over the interval [-2, 2]]:

✔️ Average rate of change of m(x) over [-2, 2]:

Average rate of change = $\frac{m(b) - m(a)}{b - a}$

Where,

a = -2, m(a) = -12

b = 2, m(b) = 4

Plug in the values into the equation

Average rate of change = $\frac{4 - (-12)}{2 - (-2)}$

= $\frac{16}{4}$

Average rate of change = 4

✔️ Average rate of change of n(x) over [-2, 2]:

Average rate of change = $\frac{n(b) - n(a)}{b - a}$

Where,

a = -2, n(a) = -6

b = 2, n(b) = 6

Plug in the values into the equation

Average rate of change = $\frac{6 - (-6)}{2 - (-2)}$

= $\frac{12}{4}$

Average rate of change = 3

✔️ Average rate of change of q(x) over [-2, 2]:

Average rate of change = $\frac{q(b) - q(a)}{b - a}$

Where,

a = -2, q(a) = -4

b = 2, q(b) = -12

Plug in the values into the equation

Average rate of change = $\frac{-12 - (-4)}{2 - (-2)}$

= $\frac{-8}{4}$

Average rate of change = -2

✔️ Average rate of change of p(x) over [-2, 2]:

Average rate of change = $\frac{p(b) - p(a)}{b - a}$

Where,

a = -2, p(a) = 12

b = 2, p(b) = -4

Plug in the values into the equation

Average rate of change = $\frac{-4 - 12}{2 - (-2)}$

= $\frac{-16}{4}$

Average rate of change = -4

The answer is D. Only p(x) has an average rate of change of -4 over [-2, 2]

3 0

2 years ago

Select all expressions that are equivalent to 64

pochemuha

Answer:

Step-by-step explanation:

What do you man what expressions or just expressions in general.

4 0

3 years ago

How do I solve this literal equation? <br> 15 points

kati45 [8]

Answer:

$\pi = \frac{A}{2r^2 + 2rh}$

Step-by-step explanation:

First, we need to isolate $\pi$ by taking it common from both terms on the right:

$A=2\pi r^2 + 2\pi rh\\A=\pi (2r^2 + 2rh)$

Now, since we want $\pi$ in terms of the other variables, we can divide the left hand side (A) by whatever is multiplied with $\pi$ on the right hand side. Then we will have an expression for $\pi$ . Shown below:

$A=\pi (2r^2 + 2rh)\\\pi = \frac{A}{2r^2 + 2rh}$

This is the xpression for $\pi$

7 0

2 years ago