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nika2105 [10]
3 years ago
10

Geometry Math

Mathematics
1 answer:
Ghella [55]3 years ago
3 0

Answer:

The. angle is 72 and the supplement is 108

Step-by-step explanation:

Supplementary agnles are two angles with a sum of 180. So for example, two right angles would be supplementary.

Once again lets break this down by putting it into an equation. The supplement will be x. We know that 180 - x ( the supplement) will be equal to the angle but the angle is 2/3 the supplement.

Your equation should look like this x = 2/3 (180 - x).

Then we're going to multiply both sides by 3 to get 3x = 2 (180 - x)

You should distribute the 2 on the right side to then get 3x = 360 - 2x

You want to get x by itself but you can't make it just disappear because you need to keep your equation balanced. You're going to need to add 2x to both sides making your equation 5x = 360.

then you're going to divide 360 by 5 to get x = 72

subtract 72 (your angle) from 180 to get 108 which is your supplement.

If it's a bit confusing feel free to msg me and I'll do my best to explain it a bit better ^^;

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Two types of shipping boxes are shown below. What is the difference in the surface areas, in square feet, of the two boxes
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*see attachment showing the 2 boxes

Answer:

3 ft²

Step-by-step explanation:

==>Given:

Box J with the following dimensions:

L = 4.5ft

W = 3ft

H = 2ft

Box F:

L = 3ft

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H = 3ft

==>Required:

Difference between the surface area of box J and box F

==>Solution:

Surface area = 2(WL + HL + HW)

=>S.A of box J = 2(3*4.5 + 2*4.5 + 2*3)

= 2(13.5 + 9 + 6)

= 2(28.5)

S.A of box J = 57 ft²

=>S.A of box F = 2(3*3 + 3*3 + 3*3)

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S.A of box F = 54 ft²

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5 0
3 years ago
The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st
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Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

v=\frac{d}{t}.

Applying this to our problem we have that

v=\frac{200m}{6.509s}= 30.726m/s.

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that v=\frac{d}{t}. This formula implies that

  1. t=\frac{d}{v}.

First, observer that 19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s.

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.

Then, applying 1) we have that

t=\frac{200m}{36.003m/s}=5.5549s.

So, Sam Whittingham’s time through the 200 m was 5.5549s.

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