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nika2105 [10]
3 years ago
10

Geometry Math

Mathematics
1 answer:
Ghella [55]3 years ago
3 0

Answer:

The. angle is 72 and the supplement is 108

Step-by-step explanation:

Supplementary agnles are two angles with a sum of 180. So for example, two right angles would be supplementary.

Once again lets break this down by putting it into an equation. The supplement will be x. We know that 180 - x ( the supplement) will be equal to the angle but the angle is 2/3 the supplement.

Your equation should look like this x = 2/3 (180 - x).

Then we're going to multiply both sides by 3 to get 3x = 2 (180 - x)

You should distribute the 2 on the right side to then get 3x = 360 - 2x

You want to get x by itself but you can't make it just disappear because you need to keep your equation balanced. You're going to need to add 2x to both sides making your equation 5x = 360.

then you're going to divide 360 by 5 to get x = 72

subtract 72 (your angle) from 180 to get 108 which is your supplement.

If it's a bit confusing feel free to msg me and I'll do my best to explain it a bit better ^^;

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mel-nik [20]

Answer:

Max = (6,0); min = (-2, 4)  

Step-by-step explanation:

1. Summarize the constraints

\text{Constraints} = \begin{cases}(a)\qquad 2x - y  & \leq 12\\(b)\qquad 4x+ 2y & \geq 0\\(c) \qquad x + 2y  & \leq 6\\ \end{cases}

2. Optimization equation

z = 5x + 2y

3. Graph the constraints to identify the feasible region

See the figure below.

The "TRUE" regions for each graph are the shaded areas to the side of the line indicated by the arrows.

The "feasibility region" is the dark green area where all three areas overlap and all three conditions are satisfied.

5. Determine the points of intersection among the constraints  

(i) Constraints (a) and (b)

\begin{array}{rcr}2x - y  & = & 12\\4x + 2y & = & 0\\4x - 2y & = & 24\\8x&=&24\\x & = & \mathbf{3}\\6 - y & = & 12\\-y & = &6\\y & = & \mathbf{-6}\\\end{array}\\

The lines intersect at (3,-6).

(ii) Constraints (a) and (c)

\begin{array}{rcr}2x - y  & = & 12\\x + 2y & = & 6\\4x - 2y & = &24\\5x & = & 30\\x & = & \mathbf{6}\\6 + 2y & = & 6\\2y & = &0\\y & = & \mathbf{0}\\\end{array}

The lines intersect at (6,0).

(iii) Constraints (b) and (c)

\begin{array}{rcr}4x+ 2y &= & 0\\x + 2y  &=& 6\\3x & = &  -6\\x & = & \mathbf{-2}\\-2 +2y & = & 6\\2y & = &8\\y & = & \mathbf{4}\\\end{array}

The lines intersect at (-2,4).

6. Determine the x- and y-intercepts of the feasible region

The five black dots at (3,-6), (6,0), and (-2,4) are the vertices of the polygon that represents the feasible region.

Each vertex is a possible maximum or minimum of z.  

7. Calculate the maxima and minima

Calculate z at each of the vertices.

(i) At (-2,4)

z = 5x + 2y = 5(-2) + 2(4) = -10 + 8 = 2

(ii) At (3,-6)

z =  5(3) + 2(-6) = 15 - 12 = 3

(iii) At (6,0)

z = 5(6)+ 2(0) = 30 + 0 = 30

The maximum of z occurs at (6,0).

The minimum of z occurs at (-2, 4).

 

7 0
3 years ago
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