Question

Point P is located at (−2, 7), and point R is located at (1, 0). Find the y value for the point Q that is located two over three the distance from point P to point R.

Answer 1

Answer:

$y_Q=\dfrac{21}{5}=4.2$

Step-by-step explanation:

If the point Q that is located two over three the distance from point P to point R, then PQ:QR=2:3.

Use formula to find the coordinates of the point Q:

$x_Q=\dfrac{3x_P+2x_R}{3+2}\\ \\y_Q=\dfrac{3y_P+2y_R}{3+2}$

In your case, P(-2,7) and R(1,0), then

$x_Q=\dfrac{3\cdot (-2)+2\cdot 1}{3+2}=\dfrac{-4}{5}\\ \\y_Q=\dfrac{3\cdot 7+2\cdot 0}{3+2}=\dfrac{21}{5}$