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andreyandreev [35.5K]
2 years ago
8

I need help finding the answer to this question on edge.

Mathematics
1 answer:
Aliun [14]2 years ago
6 0

Answer:

6

Step-by-step explanation:

We need to evaluate :-

\rm\implies \displaystyle\rm\sum^4_n   (-1)^n (3n + 2 )

Here the \Sigma is the sum operator . And here we need to find the sum from n = 1 to n = 4 . We can write it as ,

\rm\implies (-1)^1 ( 3*1 +2) + (-1)^2 ( 3*2+2) + (-1)^3(3*3+2) + (-1)^4(3*4+2)

Now we know that for odd powers of -1 , we get -1 and for even powers we get 1 . Therefore ,

\rm\implies -1 ( 3 + 2 ) + 1 (6+2)+-1(9+2)+1(12+2)

Now add the terms inside the brackets and then multiply it with the number outside the bracket . We will get ,

\rm\implies -1 * 5 + 1 * 8 + -1*11 + 1*14 \\\\\rm\implies -5 + 8 - 11 + 14 \\\\\rm\implies\boxed{\quad 6 \quad}

<u>Hence</u><u> the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>6</u><u>.</u>

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