All categories

3 years ago

What is the distance between the p&ints (8, 3) and (8, - 6) ?

Mathematics

2 answers:

NeTakaya3 years ago

7 0

Answer:

$\displaystyle 9\:units$

Step-by-step explanation:

Use the <em>Distance Formula</em>:

$\displaystyle \sqrt{[-x_1 + x_2]^2 + [-y_1 + y_2]^2} = D \\ \\ \sqrt{[-8 + 8]^2 + [-3 - 6]^2} = \sqrt{0^2 + [-9]^2} = \sqrt{0 + 81} = \sqrt{81} = 9$

Since we are talking about distance, we ONLY want the NON-NEGATIVE root.

I am joyous to assist you anytime.

baherus [9]3 years ago

5 0

Answer:

Using distance formula:

$d = \sqrt{(8 - 8 {)}^{2} + ( - 6 - 3) {}^{2} } = 9$

Answer: 9 units

You might be interested in

I need help please help

Mademuasel [1]

Answer:

Step-by-step explanation:

Note that 28 + 110 + 42 = 180, and that 28 + 42 + 110 = 180 also.

Since all three angles of one triangle are the same as the corresponding angles of the other triangle, the triangles are similar.

8 0

3 years ago

Solve (1/81)^x*1/243=(1/9)^−3−1 by rewriting each side with a common base.

elena55 [62]

Answer:

$x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]$

Step-by-step explanation:

you have the following formula:

$(\frac{1}{81})^{\frac{x}{243}}=(\frac{1}{9})^{-3}-1$

To solve this equation you use the following properties:

$log_aa^x=x$

Thne, by using this propwerty in the equation (1) you obtain for x

$log_{(\frac{1}{81})}(\frac{1}{81})^{\frac{x}{243}}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\\frac{x}{243}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]$

8 0

3 years ago

A triangle is formed using three given side lengths. Do these lengths always forma unique triangle? Explain.

ollegr [7]

No, these do not always forma unique triangles because it depends on what size your sides are because if you have 3 sides of the same length then that’s a equilateral and if you have two sides of the same length and one side that’s not then that would be an Isosceles triangle and if you had no sides of the same length then that would be a scalene triangle.

6 0

3 years ago

Simplify x^3y^4/3y^4

yan [13]

The given expression is:
(x^3 * y^4) / (3y^4)

We can notice that the term y^4 is a common term found in both the numerator and the denominator of the given expression, therefore, we can cancel this term from the both numerator and denominator (as if you divided both numerator and denominator by y^4).

Doing this, we will have the simplified form of the expression as follows:
(x^3) / (3)

4 0

3 years ago

Read 2 more answers

Pleaseeeee helpppppp!!

Sergio [31]

Answer: The equation of the circle as specified is (x+5)² + (y -1)² = 25

Step-by-step explanation: Use the Pythagorean Theorem to calculate the length of the radius from the coordinates given for the triangle location: A(-1,4), B(-1,1) and C(-5,1)

subtract y-values of A & B 4-1=3 AB = 3

subtract x-values of B &C -5-(-1) =4 BC=4 3² + 4² = 9 + 16 = 25

√25 = 5 AC = 5 That is the radiuus of the circle.

The sides of the triangle are AB=3, BC=4, AC=5.

Use the equation for a circle:

( x - h )² + ( y - k )² = r², where ( h, k ) is the center and r is the radius.

Use the coordinates of C, (-5, 1) as h and k in the equation

Substituting those values, we have (x -[-5])² + (y -[1])² = 5²

Simplify: (x+5)² + (y -1)² = 25

A graph of the circle is attached. The radius is AC, between the center C (-5,1) and A( -1,4) on the circumference. (Sorry, I still need to learn how to create line segments!)

8 0

3 years ago