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3 years ago

What is the distance between the p&ints (8, 3) and (8, - 6) ?

Mathematics

2 answers:

NeTakaya3 years ago

7 0

Answer:

$\displaystyle 9\:units$

Step-by-step explanation:

Use the <em>Distance Formula</em>:

$\displaystyle \sqrt{[-x_1 + x_2]^2 + [-y_1 + y_2]^2} = D \\ \\ \sqrt{[-8 + 8]^2 + [-3 - 6]^2} = \sqrt{0^2 + [-9]^2} = \sqrt{0 + 81} = \sqrt{81} = 9$

Since we are talking about distance, we ONLY want the NON-NEGATIVE root.

I am joyous to assist you anytime.

baherus [9]3 years ago

5 0

Answer:

Using distance formula:

$d = \sqrt{(8 - 8 {)}^{2} + ( - 6 - 3) {}^{2} } = 9$

Answer: 9 units

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