According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7
Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.
Given,
n = 66
We know that,
According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:

Here, n is equal to 66 and by substituting the value to the equation we get:

k = 7.0444
k ≈ 7
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Answer:
x = 6, x = - 6
Step-by-step explanation:
Given
y = x² - 36
To find the zeros let y = 0, that is
x² - 36 = 0 ← x² - 36 is a difference of squares and factors in general as
a² - b² = (a - b)(a + b), thus
x² - 36 = 0
x² - 6² = 0
(x - 6)(x + 6) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 6 = 0 ⇒ x = 6
x + 6 = 0 ⇒ x = - 6
Answer:
100 degrees
Step-by-step explanation:
The measure of angle T is 100 degrees.
Answer:x=2
Step-by-step explanation: 2x-4=0
2x-4=0
+4 +4
2x=4
2x/2=4/2
X=2
Answer:
1) a = 110
2) b = 65
3) c = 115 d= 65 e = 115
How I found the last one?
The whole thing equals 360.
d is equal to 65 so I added those together.
That equals 130. So i subtracted that from 360.
I got 230. Next, I divided that by 2 to get the final 2 angles.