We know from the question that John can drive 37.6 miles per 1 gallon in the city, and 42.3 miles per gallon on the highway. Therefore, B is correct because the other options are just incorrect and contradict the statements made in the question. John wouldn't use 37.6 gallons of gas to drive a single mile, that just doesn't make sense. B. John's car uses 1 gallon of gas to drive 37.6 miles in the city.
Solve for x:5 x + 3 (x + 4) = -20
3 (x + 4) = 3 x + 12:3 x + 12 + 5 x = -20
Grouping like terms, 5 x + 3 x + 12 = (5 x + 3 x) + 12:(5 x + 3 x) + 12 = -20
5 x + 3 x = 8 x:8 x + 12 = -20
Subtract 12 from both sides:8 x + (12 - 12) = -12 - 20
12 - 12 = 0:8 x = -20 - 12
-20 - 12 = -32:8 x = -32
Divide both sides of 8 x = -32 by 8:(8 x)/8 = (-32)/8
8/8 = 1:x = (-32)/8
The gcd of -32 and 8 is 8, so (-32)/8 = (8 (-4))/(8×1) = 8/8×-4 = -4:Answer: x = -4
A^2 + b^2 = c^2....where a and b are the legs, c is the hypotenuse
3^2 + b^2 = 7^2
9 + b^2 = 49
b^2 = 49 - 9
b^2 = 40.....take sqrt of both sides, eliminating the ^2
b = square root of 40 <==
The answer is 2.6 m/s
The speed (v) is distance (d) through time (t).
v = d/t
We know:
d = 390 m
t = 150 s
v = d/t
v = 390 m / 150s
v = = 2.6 m/s
