The solution to given system of equations is x = 2 and y = -5
<em><u>Solution:</u></em>
<em><u>Given the system of equations are:</u></em>
4x + y = 3 ---------- eqn 1
-2x + 3y = -19 ---------- eqn 2
We have to find the solution to above system of equations
<em><u>We can solve the system by substitution method</u></em>
From eqn 1,
4x + y = 3
Isolate y to one side
y = 3 - 4x ----------- eqn 3
<em><u>Substitute eqn 3 in eqn 2</u></em>
-2x + 3(3 - 4x) = -19
-2x + 9 - 12x = -19
Combine the like terms
-14x = -19 - 9
-14x = -28
Divide both sides of equation by -14
<h3>x = 2</h3>
<em><u>Substitute x = 2 in eqn 3</u></em>
y = 3 - 4(2)
y = 3 - 8
<h3>y = -5</h3>
Thus the solution is x = 2 and y = -5
Answer: 152 units square 2
Step-by-step explanation:
Answer:
1/2 + 2/3 + 5/4 = 29/
12
= 2 5/ 12 ≅ 2.4166667
Step-by-step explanation:
Add: 1/
2 + 2/
3 = 1 · 3/
2 · 3 + 2 · 2/
3 · 2 = 3/
6 + 4/
6 = 3 + 4/
6 = 7/
6
For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(2, 3) = 6. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 2 × 3 = 6. In the next intermediate step, the fraction result cannot be further simplified by canceling.
In words - one half plus two thirds = seven sixths.
Add: the result of step No. 1 + 5/
4 = 7/
6 + 5/
4 = 7 · 2/
6 · 2 + 5 · 3/
4 · 3 = 14/
12 + 15/
12 = 14 + 15/
12
= 29/
12
For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(6, 4) = 12. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 6 × 4 = 24. In the next intermediate step, the fraction result cannot be further simplified by canceling.
In words - seven sixths plus five quarters = twenty-nine twelfths.
<em>hope it helps...</em>
<em>correct me if I'm wrong...</em>
Sum of infinite series of a GS is a1 / (1-r)
so here it is 65 / (1 - 1/6) = 65 / 5/6 = 65*6 / 5 = 78 answer
