Answer:
There is no point of the form (-1, y) on the curve where the tangent is horizontal
Step-by-step explanation:
Notice that when x = - 1. then dy/dx becomes:
dy/dx= (y+2) / (2y+1)
therefore, to request that the tangent is horizontal we ask for the y values that make dy/dx equal to ZERO:
0 = ( y + 2) / (2 y + 1)
And we obtain y = -2 as the answer.
But if we try the point (-1, -2) in the original equation, we find that it DOESN'T belong to the curve because it doesn't satisfy the equation as shown below:
(-1)^2 + (-2)^2 - (-1)*(-2) - 5 = 1 + 4 + 2 - 5 = 2 (instead of zero)
Then, we conclude that there is no horizontal tangent to the curve for x = -1.
Which part needs answering ?
Answer:
no
Step-by-step explanation:
no,
it is not in the form
To estimate this we can do it like this:-
<span>
Way #1
3.4 = 3
6 = 6
3 </span>÷ 6 = <span>0.5
So, to estimate 3.4 </span>÷ 6 we round 3.4 to the nearest whole number and den divide. Den d answer is our estimated answer!
3.4 ÷ 6 = 0.5
Hope I helped ya!!
