1/2 of the class are 5th and 4th
1/2 of 96= 48
1/4 of 48 =12
Answer:
4.24 km
Step-by-step explanation:
The x-component of the displacement after the turn is ...
d2·cos(θ) = (3.38 km)cos(65.3°) ≈ 1.41239 km
Adding this to the displacement before the turn, we have ...
x-component of displacement = 2.83 km + 1.41 km = 4.24 km
The equation equivalent to this formula would be D)b1=2A-b2
1.50s + 0.75f = 116.25
2f = s
1.50(2f) + 0.75f = 116.25
3f + 0.75f = 116.25
3.75f = 116.25
f = 116.25/3.75
f = 31...31 friday papers
2f = s
2(31) = s
62 = s <=== 62 sunday papers
Using theorem about secant segments we can write,
AB*AH=AG*AC
AC=4,
CG=6
AG=AC+CG=4+6=10
AH=3
AB= AH+HB=AH+x=3+x
(3+x)*3=10*4
9+3x=40
3x=40-9
3x=31
x=31/3≈10.3
HB≈10.3
EG=HB/2 (as radius and diameter)
EG=10.3/2≈5.2