PLEASE HELP ME!! Simplify by multiplying the LCD
1 answer:
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Answer:
The probability that a defective rod can be salvaged = 0.50
Step-by-step explanation:
Given that:
A machine shop produces heavy duty high endurance 20-inch rods
On occasion, the machine malfunctions and produces a groove or a chisel cut mark somewhere on the rod.
If such defective rods can be cut so that there is at least 15 consecutive inches without a groove.
Then; The defective rod can be salvaged if the groove lies on the rod between 0 and 5 inches i.e ( 20 - 15 )inches
Now:
P(X ≤ 5) =
= 0.25
P(X ≥ 15) =
= 0.25
The probability that a defective rod can be salvaged = P(X ≤ 5) + P(X ≥ 15)
= 0.25+0.25
= 0.50
∴ The probability that a defective rod can be salvaged = 0.50
Answer:
B
Step-by-step explanation:
you have probably finished the quiz by now but anyway
so first flip the picture so that u see the cylinder standing on its base
12 is the diameter and 8 the height
12/2 = 6=radius
finally u do
πrh
3.14**8
**i simplified π so the answer will be 904.32**
please vote if you found this helpful :)