Answer:
We are given that angle AOB is a central angle of circle O and that angle ACB is a circumscribed angle of circle O. We see that AO ≅ BO because
✔ all radii of the same circle are congruent.
We also know that AC ≅ BC since
✔ tangents to a circle that intersect are congruent.
Using the reflexive property, we see that
✔ side CO is congruent to side CO.
Therefore, we conclude that △ACO is congruent to △BCO by the
✔ SSS congruence theorem.
please mark brainliest.... hope you have a great day ! XD
Answer:
The answer is 5q + 9.
Step-by-step explanation:
1) Collect like terms.

2) Simplify.

<u>hence</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>5q</u><u> </u><u>+</u><u> </u><u>9</u><u>.</u>
Answer:
see explanation
Step-by-step explanation:
The x- intercept is where the graph crosses the x- axis, that is
(
, 0 )
The y- intercept is where the graph crosses the y- axis, that is
(0, 1 )
Answer:
its rather 3 or 5 its prob 3
Step-by-step explanation: