Answer:
The perimeter of triangle PQR is 17 ft
Step-by-step explanation:
Consider the triangles PQR and STU
1. PQ ≅ ST = 4 ft (Given)
2. ∠PQR ≅ ∠STU (Given)
3. QR ≅ TU = 6 ft (Given)
Therefore, the two triangles are congruent by SAS postulate.
Now, from CPCTE, PR = SU. Therefore,

Now, side PR is given by plugging in 3 for 'y'.
PR = 3(3) - 2 = 9 - 2 = 7 ft
Now, perimeter of a triangle PQR is the sum of all of its sides.
Therefore, Perimeter = PQ + QR + PR
= (4 + 6 + 7) ft
= 17 ft
Hence, the perimeter of triangle PQR is 17 ft.
2.0 + 0.5 + 0.01 hope this helps
Answer:
65.52 square feet
Step-by-step explanation:
to find area of a rhombus with the diagonals multiply them together and divide by two.
10.4 x 12.6 = 131.04
131.04/2 = 65.52 square ft
Answer:
y = 6/5x - 24/5
Step-by-step explanation:
The two points we are given are (4, 0) and (9, 6). First, find the slope.
m = 6 - 0/9 - 4 = 6/5
Next, insert the values into the point-slope form formula. I'll use (4, 0) as the coordinates.
y - 0 = 6/5(x - 4)
y = 6/5x - 24/5
14 because u are adding both factor and u are adding