Solution-
First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I
Total number of ways of selection of 4 letters from 9 alphabets = 9C4
=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126
The number of ways of arranging these 4 numbers = 4! = 24
∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024
∴ option number 2 is correct.
They are (0,6) because if the center of dilation is point A which means it does not change, while both other points increase their distance from point A by a factor of two (double)
Answer: B. Square
Step-by-step explanation:
- All sides of a square have the same length
- All four angles of a square = 90°
- A square has two parallel sides
Answer:
B
Step-by-step explanation:
I added all of then and then subtracted 47 from the 50.
Ok so first you need to put w and x in the equation —-> 13-0.5(10)+6(1/2) and now you just solve -0.5 times 10 is -5 so 13-(-5)+6(1/2) now multiply 6 times 1/2 which is 3 so now we have 13-(-5)+3= 21