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3 years ago

Which series of transformations shows that triangle A is congruent to triangle B?

Mathematics

2 answers:

Vilka [71]3 years ago

5 0

I would say A
hope that helps!!!

Alecsey [184]3 years ago

5 0

The answer is A: reflect triangle a over the x axis translate it 4 units to the right and reflect it over the y axis

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Which system of equations will yield the same solution as x-y=3 2x-3y=-1

laiz [17]

Answer: Is there some answer choices? Because I can't help if I don't have any choices.

Step-by-step explanation:

5 0

3 years ago

Cual es el resultado?/ who is the answer? -m+4-(-m)=

Debora [2.8K]

Answer:

$-m+4-(-m) = -m+4+m \\ = 4$

8 0

3 years ago

Look at the figure shown below

Setler79 [48]

Answer:

Answer is given below with explanations.

Step-by-step explanation:

Answer is option 1) 85 : 51

$given \: that \: \\ triangle \: SPT \: is \: similar \: to \: triangle \: QPR \\ corresponding \: sides \: of \: similar \: \\ triangles \: are \: in \: proportion \\ then \: \\ \frac{SP}{ QP} = \frac{PT }{ PR} \\ \frac{3x}{3x + 24} = \frac{51}{85} \\ taking \: reciprocal \: on \: both \: sides \\ \frac{3x + 24}{3x} = \frac{85}{51}$

Option 1 is correct.

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

6 0

3 years ago

Help me with question a please ! With full workings !

frosja888 [35]

A)

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
P&({{ 0.5}}\quad ,&{{ 0}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$

$\bf QP=\sqrt{(0.5-0)^2+(0-2)^2}\implies QP=\sqrt{0.5^2+2^2}
\\\\\\
QP=\sqrt{\left( \frac{1}{2} \right)^2+4}\implies QP=\sqrt{ \frac{1^2}{2^2}+4}\implies QP=\sqrt{\frac{1}{4}+4}
\\\\\\
QP=\sqrt{\frac{17}{4}}\implies QP=\cfrac{\sqrt{17}}{\sqrt{4}}\implies QP=\cfrac{\sqrt{17}}{2}$

b)

since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP

thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)

c)

what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
R&({{ -0.5}}\quad ,&{{ 0}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-0.5-0}\implies \cfrac{-2}{-0.5}$

$\bf m=\cfrac{\frac{-2}{1}}{-\frac{1}{2}}\implies \cfrac{-2}{1}\cdot \cfrac{2}{-1}\implies 4
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=4(x-0)\implies y=4x+2\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}$

7 0

3 years ago

15. An irregular pentagon has side lengths of (x + 3), (2x - 4), (4x + 5),

Kobotan [32]

Answer:

A. 11x-3

Step-by-step explanation:

perimeter=sum of all sides

=(x+3)+(2x-4)+(4x+5)+(3x-1)+(x)

= 11-3

3 0

3 years ago