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statuscvo [17]
3 years ago
14

Serena invests $2500 for 3 years and 6 months and earns $328.13. What was the rate of interest? Explain how you solved.

Mathematics
1 answer:
NARA [144]3 years ago
6 0

Answer:

4.38%

Step-by-step explanation:

<em>Assuming simple interest</em>, we start by writing the formula for simple interest.

SI=Prt

Where

SI is the interest amount (328.13)

P is the principal amount (2500)

r is the rate of interest (what we need to find)

t is the time, in years (t = 3)

Since we want rate of interest, we re-arrange the formula to get r in terms of the other variables. Shown below:

SI=Prt\\r=\frac{SI}{Pt}

Now we simply plug-in the information we know and find r:

r=\frac{328.13}{(2500)(3)}\\r=0.0438

To convert into percentage, we multiply by 100:

r = 0.0438 * 100 = 4.38%

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Use substitution to determine the solution of the system of equations.
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Answer:

C

Step-by-step explanation:

Work the equations out to find your answer to each, then you see the answer

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3 years ago
Tyrone runs 5 mph how far can he travel in two hours and 30 minutes
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Answer:

12.5 miles

Step-by-step explanation:

5x2.5=12.5 miles

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3 years ago
Consider the parabola given by the equation: f(x) = 4x² - 6x - 8 Find the following for this parabola: A) The vertex: Preview B)
jeyben [28]

Answer:

The vertex: (\frac{3}{4},-\frac{41}{4} )

The vertical intercept is: y=-8

The coordinates of the two intercepts of the parabola are (\frac{3+\sqrt{41} }{4} , 0) and (\frac{3-\sqrt{41} }{4} , 0)

Step-by-step explanation:

To find the vertex of the parabola 4x^2-6x-8 you need to:

1. Find the coefficients <em>a</em>, <em>b</em>, and <em>c </em>of the parabola equation

<em>a=4, b=-6, \:and \:c=-8</em>

2. You can apply this formula to find x-coordinate of the vertex

x=-\frac{b}{2a}, so

x=-\frac{-6}{2\cdot 4}\\x=\frac{3}{4}

3. To find the y-coordinate of the vertex you use the parabola equation and x-coordinate of the vertex (f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c)

f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c\\f(\frac{3}{4})=4\cdot (\frac{3}{4})^2-6\cdot (\frac{3}{4})-8\\y=\frac{-41}{4}

To find the vertical intercept you need to evaluate x = 0 into the parabola equation

f(x)=4x^2-6x-8\\f(0)=4(0)^2-6\cdot 0-0\\f(0)=-8

To find the coordinates of the two intercepts of the parabola you need to solve the parabola by completing the square

\mathrm{Add\:}8\mathrm{\:to\:both\:sides}

x^2-6x-8+8=0+8

\mathrm{Simplify}

4x^2-6x=8

\mathrm{Divide\:both\:sides\:by\:}4

\frac{4x^2-6x}{4}=\frac{8}{4}\\x^2-\frac{3x}{2}=2

\mathrm{Write\:equation\:in\:the\:form:\:\:}x^2+2ax+a^2=\left(x+a\right)^2

x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=2+\left(-\frac{3}{4}\right)^2\\x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{41}{16}

\left(x-\frac{3}{4}\right)^2=\frac{41}{16}

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

x_1=\frac{\sqrt{41}+3}{4},\:x_2=\frac{-\sqrt{41}+3}{4}

4 0
3 years ago
How do I solve this?
ra1l [238]

Answer:

(-6,1)   (2,7)

Step-by-step explanation:

y =x+5

y = x^2 +5x-7

Set the two equations equal since y=y

x+5 =  x^2 +5x -7

Subtract x from each side

x-x+5 =  x^2 +5x-x -7

5 = x^2 +4x -7

Subtract 5 from each side

5-5 = x^2 +4x -7-5

0 = x^2 +4x-12

Now we can factor the right side

What 2 numbers multiply to -12 and add to +4

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0 = (x+6) (x-2)

Using the zero product property

x+6=0    x-2=0

x=-6   x=2

We need to find y for each value of x

y = x+5           y = x+5

y = -6+5            y = 2+5

y =1                 y = 7

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3 years ago
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Katyanochek1 [597]

Answer:

w=-1.16u

Step-by-step explanation:

first you want to put the W's on one side and the U's on the other. we can do this by subtracting 4u from the left side and the right side making the equations 8w=-7u+2w.

next we want to subtract 2w from both sides making the equation 6w=-7u then we divide by 6 to get w=-1.16u

3 0
3 years ago
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