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statuscvo [17]
4 years ago
14

Serena invests $2500 for 3 years and 6 months and earns $328.13. What was the rate of interest? Explain how you solved.

Mathematics
1 answer:
NARA [144]4 years ago
6 0

Answer:

4.38%

Step-by-step explanation:

<em>Assuming simple interest</em>, we start by writing the formula for simple interest.

SI=Prt

Where

SI is the interest amount (328.13)

P is the principal amount (2500)

r is the rate of interest (what we need to find)

t is the time, in years (t = 3)

Since we want rate of interest, we re-arrange the formula to get r in terms of the other variables. Shown below:

SI=Prt\\r=\frac{SI}{Pt}

Now we simply plug-in the information we know and find r:

r=\frac{328.13}{(2500)(3)}\\r=0.0438

To convert into percentage, we multiply by 100:

r = 0.0438 * 100 = 4.38%

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Step-by-step explanation:

The Law of Cosines can be used to figure this.

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A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.
Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

t=\sqrt{\frac{2h}{a}} ,where h=height of release

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Where I=moment of inertia

a for hoop

a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}

a=\frac{g\sin \theta }{2}

a for Uniform solid cylinder

a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}

a=\frac{2g\sin \theta }{3}

a for spherical shell

a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}

a=\frac{3g\sin \theta }{5}

a for Uniform Solid

a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}

a=\frac{5g\sin \theta }{7}

time taken will be inversely proportional to the square root of acceleration

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3 years ago
A.It will stay the same
DanielleElmas [232]

Answer:

B

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Let's arrange the data set in increasing order.

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The new set is 19, 27, 27, 33, 45, 53, 90. The new median is 33.

Since 33 - 30 = 3 the answer is B.

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3 years ago
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