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oee [108]
3 years ago
7

A swimming pool is filled with water by using two taps A and B. Alone, it takes tap A 3 hours less than B to fill the same pool.

Together, they take 2 hours to fill the pool. How many hours does it take each tap to fill the swimming pools separately?
Mathematics
1 answer:
iris [78.8K]3 years ago
5 0

Answer:

Tap A 3hrs

Tap B 6hrs

Step-by-step explanation:

Let the volume of the swimming pool be Xm^3.

Now, to get the appropriate volume, we know we need to multiply the rate by the time. Let the rate of the taps be R1 and R2 respectively, while the time taken to fill the swimming pool be Ta and Tb respectively.

x/Ta= Ra

x/Tb= Rb

X/(Ra + Rb)= 2

Ta = Tb - 3

From equation 2:

X = 2( Ra + Rb)

Substituting the values of Ra and Rb Using the first set of equations

X = 2( x/Ta + x/Tb)

But Ta = Tb - 3

1/2 = 1/(Tb - 3)+ 1/Tb

0.5 = (Tb + Tb-3)/Tb(Tb - 3)

At this juncture let’s say Tb = y

0.5 = (2y - 3)/y(y - 3)

y(y-3 ) = 4y - 6

y^2 -3y - 4y + 6 = 0

y^2 -7y + 6= 0

Solving the quadratic equation, we get y =

y = Tb = 6hrs or 1hr

We remove one hour as we know that Tap A takes 3hrs left than tap B and there is nothing like negative hours

Now, we get Ta by Tb -3 = 6 - 3 = 3hrs

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Step-by-step explanation:

x

2

+

x

−

6

=

(

x

+

3

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(

x

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x

2

−

3

x

−

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=

(

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(

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Each of the linear factors occurs precisely once, so the sign of the given rational expression will change at each of the points where one of the linear factors is zero. That is at:

x

=

−

3

,

−

1

,

2

,

4

Note that when

x

is large, the

x

2

terms will dominate the values of the numerator and denominator, making both positive.

Hence the sign of the value of the rational expression in each of the intervals

(

−

∞

,

−

3

)

,

(

−

3

,

−

1

)

,

(

−

1

,

2

)

,

(

2

,

4

)

and

(

4

,

∞

)

follows the pattern

+

−

+

−

+

. Hence the intervals

(

−

3

,

−

1

)

and

(

2

,

4

)

are both part of the solution set.

When

x

=

−

1

or

x

=

4

, the denominator is zero so the rational expression is undefined. Since the numerator is non-zero at those values, the function will have vertical asymptotes at those points (and not satisfy the inequality).

When

x

=

−

3

or

x

=

2

, the numerator is zero and the denominator is non-zero. So the function will be zero and satisfy the inequality at those points.

Hence the solution is:

x

∈

[

−

3

,

−

1

)

∪

[

2

,

4

)

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