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4 years ago

An equilateral triangle has a perimeter of 15x3 33x5 feet. what is the length of each side?

Mathematics

2 answers:

yan [13]4 years ago

4 0

Answer:The answer is D. Have a nice day

Step-by-step explanation:

Archy [21]4 years ago

3 0

Answer:

$5x^3+11x^5$ feet.

Step-by-step explanation:

We have been given that an equilateral triangle has a perimeter of $15x^3+33x^5$ feet. We are asked to find the length of each side of the triangle.

Since we know that all sides of an equilateral triangle are of equal measure and the perimeter of an equilateral triangle is three times its each side length.

To find the length of each side of our given triangle, we will divide our given perimeter by 3.

$\text{Length of each side of triangle}=\frac{15x^3+33x^5}{3}$

$\text{Length of each side of triangle}=5x^3+11x^5$

Therefore, the length of each side of our given triangle is $5x^3+11x^5$ feet.

You might be interested in

The equation is________ Solve the equation x=________

Komok [63]

Answer:

7x-5 = 9

x = 2

Step-by-step explanation:

Let x be the number

7x-5 = 9

Add 5 to each side

7x-5+5 = 9+5

Divide each side by 7

7x = 14

7x/7 = 14/7

x=2

5 0

3 years ago

The answer for your question is a 1;3 because 16/48=1/3 or 1:3.

tiny-mole [99]

1:3 = 16/48 and 1/3.

Have a nice day! :D

4 0

3 years ago

If the radius of a circle with a area of 5.3 mm squared is multiplied by 5,

chubhunter [2.5K]

I'm guessing the question is meant to be "If the radius of a circle with a area of 5.3 mm squared is multiplied by 5, what will the new area be?", so i'll answer that.

Area of a circle =πr^2

5.3=πr^2, 5.3=π(5r)^2
132.5=25πr^2

6 0

3 years ago

Find the length of a diagonal of a square of side 17cm

Ronch [10]

Answer:

2*17²=length=578

apply Pythagoras theorem

8 0

3 years ago

An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y

aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average time = 23.92 minutes

s = sample standard deviation = 6.72 minutes

n = sample of times = 40

$\mu$ = population mean assembly time

Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 98% confidence interval for the population mean, $\mu$ is;

P(-2.426 < $t_3_9$ < 2.426) = 0.98 {As the critical value of z at 1% level

of significance are -2.426 & 2.426}

P(-2.426 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.426) = 0.98

P( $-2.426 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $23.92-2.426 \times {\frac{6.72}{\sqrt{40} } }$ , $23.92+2.426 \times {\frac{6.72}{\sqrt{40} } }$ ]

= [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0

3 years ago