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3 years ago

How many roots does the polynomial function, y=(x-8)(x+3)^2 have?

Mathematics

2 answers:

Scorpion4ik [409]3 years ago

7 0

Answer:

(A) 2

Step-by-step explanation:

There are two distinct roots, one of which has a multiplicity of 2.

Root 1: x=8

Root 2: x = -3

d1i1m1o1n [39]3 years ago

6 0

Answer: 2

Step-by-step explanation:

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Express the following relationship as a rate.

klasskru [66]

Answer:

3 pages per minute

Step-by-step explanation: hope this helps.

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3 years ago

please help me with it and dont just put random letters cause i dont know why u do it its not like u can buy a house with these

BartSMP [9]

Answer:

v=432cm

sA=144cm

Step-by-step explanation:

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6 0

3 years ago

Read 2 more answers

Mr. Jones wants to add a cement path around his new pool. The pool has a radius of 7 feet. The cement path will be 1 foot wide a

Aleonysh [2.5K]

The square footage of the path is 47.1 ft²

The area of a circle is:

A = πr²

Where r is the radius of the circle.

Let us assume that the pool is a circle.

Given that the pool has a radius (r₁) of 7 feet and a path 1 foot wide would go round the pool.

Radius of pool and cement path (r₂) = 7 ft + 1 ft = 8 ft.

The square footage of the path = πr₂² - πr₁² = π*8² - π * 7² = 47.1 ft²

Hence The square footage of the path is 47.1 ft²

Find out more at: brainly.com/question/23328170

7 0

2 years ago

20 kilograms to pounds

xeze [42]

Answer:

44.0925 pounds

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

For what value of k will the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent?

konstantin123 [22]

Answer:

After solve the equations we get value of k=3

Step-by-step explanation:

We need to find value of k for which the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent.

If the lines are concurrent, they pass through same point.

Let:

$x+2y=0--eq(1)\\ 3x-4y-10=0--eq(2)\\ 5x+ky-7=0--eq(3)$

First solving equation 1 and 2 to find values of x and y

From eq(1) we find value of x and put it in eq(2)

$From \ eq(1) x+2y=0\\x=-2y\\Put x=-2y \ in \ eq(2)\\3x-4y-10=0\\3(-2y)-4y-10=0 \\-6y-4y=10\\-10y=10\\y=\frac{10}{-10}\\y=-1$

After solving we get value of y=-1

Now putting in eq(1) to get value of x

$x+2y=0\\x+2(-1)=0\\x-2=0\\x=2$

So, Value of x= 2

Now put value of x=2 and y=-1 into eq(3) to find value of k

$5x+ky-7=0\\5(2)+k(-1)-7=0\\10-k-7=0\\-k+3=0\\-k=-3\\k=3$

So, After solve the equations we get value of k=3

4 0

3 years ago