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ArbitrLikvidat [17]

2 years ago

9

A miner descended 1400 feet into a mine from the mine's entrance. While in the mine, he then rose 800 feet and then descended 45

0 feet. What was the miner's net gain or loss in altitude from the entrance of the mine? A. –1050 ft B. 2650 ft C. –2650 ft D. 250 ft

2 answers:

Semmy [17]2 years ago

8 0

Your answer is C. -2650

postnew [5]2 years ago

7 0

The correct answer is A.-1050

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vovangra [49]

Answer:

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Step-by-step explanation:

radius is the half of one whole circle so

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Eric owns and operates the hot food truck.The expression 3.25b+2h gives the cost of burgers and h hot dogs.What is the cost of 4

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Explain how to find 40×50 using mental math

Naya [18.7K]

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2 years ago

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Vedmedyk [2.9K]

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2 years ago

Solve the equation: \frac{2}{3}t=\frac{5}{9} (hint: reciprocal)

Aleks04 [339]

Given:

$\frac{2}{3}t=\frac{5}{9}$ $\text{ We know that the reciprocal of }\frac{2}{3}\text{ is }\frac{3}{2}\text{.}$

Multiply both sides by 3/2, we get

$\frac{3}{2}\times\frac{2}{3}t=\frac{3}{2}\times\frac{5}{9}$

Cancel out the common multiples, we get

$t=\frac{1}{2}\times\frac{5}{3}$

$t=\frac{1\times5}{2\times3}$

$t=\frac{5}{6}$

The solution of the given equation is

$t=\frac{5}{6}$

or

$t=0.8333.$

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5 months ago