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2 years ago

What is the best way to classify each equation?

Mathematics

1 answer:

Rus_ich [418]2 years ago

6 0

1. identity → distributive property on the right gives you 8x + 24 same as right

2. contradiction → left side simplified 4x + 18; right side simplified 4x + 16

3. neither → left side simplified 21x - 14; right side 20x - 13

4. identity → left side simplified 5x - 20; right side simplified 5x - 20

Identity equations have infinitely many solutions (any real number will work)
Contradiction equations have no solution (variable will cancel out and remaining statement is false)
Neither will have one solution for the equation (x coefficients are different)

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Terrence solves the problem and finds 53.04 x 4.6 = 2,439.84. Tara says that his product is incorrect. Fill in the blanks to hel

Sati [7]

Answer:tara was right terrence was close but he put the(.) in the wrong spot the correct answer is 243.984 but terrence put 2439.84

^ ^

l l

Read more on Brainly.com - brainly.com/question/6907475#readmore

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

1011+111 in binary form

Ann [662]

Answer:

10010

Step-by-step explanation:

$1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$111=1(2)^2+1(2)^1+1(2)^0$

So $1011+111$ gives us:

$1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$+$

$1(2)^2+1(2)^1+1(2)^0$

-----------------------------------------------------

Combine like terms:

$1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0$

$1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0$

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace $2^0$ with 1 and $2$ with $(2)^1$ :

$1(2)^3+1(2)^2+(2)^2+(2)^1(1)$

I want a $2^0$ number:

$1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0$

Combine like terms:

$1(2)^3+2(2)^2+1(2)^1+0(2)^0$

$2(2)^2=2^3$ :

$1(2)^3+2^3+1(2)^1+0(2)^0$

Combine like terms:

$2(2)^3+1(2)^1+0(2)^0$

We can rewrite the first term by law of exponents:

$2^4+1(2)^1+0(2)^0$

$1(2)^4+1(2)^1+0(2)^0$

So the binary form is:

$10010$

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

1 0 1 1

+ 1 1 1

------------------------------

(1) (1) (1)

1 0 1 1

+ 1 1 1

------------------------------

1 0 0 1 0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0

3 years ago

In a right triangle, the measure of one acute angle is 12 more than twice the measure of the other acute angle. Find the measure

soldi70 [24.7K]

Given:

In a right triangle, the measure of one acute angle is 12 more than twice the measure of the other acute angle.

To find:

The measures of the 2 acute angles of the triangle.

Solution:

Let x be the measure of one acute angle. Then the measure of another acute is (2x+12).

According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees. So,

$x+(2x+12)+90=180$

$3x+102=180$

$3x=180-102$

$3x=78$

Divide both sides by 3.

$x=\dfrac{78}{3}$

$x=26$

The measure of one acute angle is 26 degrees. So, the measure of another acute angle is:

$2x+12=2(26)+12$

$2x+12=52+12$

$2x+12=64$

Therefore, the measures of two acute angles are 26° and 64° respectively.

8 0

2 years ago

The product-3 and t is greater than 11

PSYCHO15rus [73]

Answer:

i am pretty sure its 8

Step-by-step explanation:

because a negative plus a positive = wichever one is bighger and 8 is bigger than 3 so 11 is positive. 8 +3 = 11

6 0

3 years ago

7.15z + 2.3z = ?z i hate math

Nitella [24]

Answer:

9.45z :)

Step-by-step explanation:

3 0

2 years ago