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Stels [109]
3 years ago
9

Find x, if f(x) = 12 and Ax) = 3x. A.36 B.12 C.4 D.3​

Mathematics
2 answers:
SpyIntel [72]3 years ago
5 0

Answer:

A. 36

Step-by-step explanation:

Keith_Richards [23]3 years ago
3 0

Answer: The answer is 4...

Explanation: this is a simple equation if you're trying to find X and f(x) = 12  but A(x) equals 3x your basically doing 3 times what equals 12 which in this case that would be 4 (well in any case it would be 4) I know this is confusing so hear me out (sorry)

f(x) = 12

A(x) = 3x  

3 x 4 = 12

x = 4

Like I said sorry if this makes you confused but the answer is 4 :)

brainliest? (even though I'm two weeks late)

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Free_Kalibri [48]

Answer:

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6 0
3 years ago
2x+3x^2(4x-5)<br> please helpppp asap
Aliun [14]

Here's my step-by-step explanation:

We're just gonna factor.

If your teacher has spoken of FOIL, then he/she has probably said that it means First Outer Inner Last and that it helps with distributing problems like these.

Right, so let's get to it.

2x+3x^2 (4x-5)\\2x(4x-5)+3x^2(4x-5)\\2x(4x) + 2x(-5) + 3x^2(4x) + 3x^2(-5)

Can you see the FOIL method being spread out here? Let's keep going.

2x(4x) + 2x(-5) + 3x^2(4x) + 3x^2(-5)\\8x^2 + (-10x) + 12x^3 + (-15x^2)\\12x^3 + 8x^2 - 15x^2 -10x\\12x^3 -7x^2 -10x

Hope this helps, and let me know if I made a mistake! ^_^

7 0
3 years ago
How many cities have an average temperature at or below freezing in the month of January
Lisa [10]
Jan. 2014 Average High                Historical Average High
New York:         38 F (3.3 C)          36 F (2.2 C)
Los Angeles:     76 F (24.4 C)        68 F (20 C)
Chicago:            27 F (-2.7 C)          32 F (0 C)
Houston:          64 F (17.8 C)          63 F (17.2 C)
Philadelphia:   40 F (4.4 C)           41 F (5 C)
Phoenix:           73 F (22. 8 C)         67 F (19.4 C)
San Antonio:   66 F (18.9 C)           63 F (17.2 C)
San Diego:        72 F (22.2 C)          65 F (18.3 C)
Dallas:               58 F (14.4 C)           57 F (13.9 C)
<span>San Jose:          66 F (18.9 C)           58 F (14.4 C)</span>
6 0
3 years ago
Please dont put any files or links. answer each equation please.
Lynna [10]

Answer:

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7 0
3 years ago
If a positive integer is equal to the following product: 25b3c425b3c4, where b and c are distinct prime numbers greater than 2,
Vlad [161]

Answer: 64 distinct even factors

Step-by-step explanation:

let the 2 distinct numbers be b and c and the integer is expected to be 25b3c425b3c4

since b, c > 2 and prime numbers,

potential options include 3, 5, and 7

hence the likelihoods are (b = 3, c = 5), (b = 5, c = 3), (b = 3, c = 7), (b = 7, c = 3), (b = 5, c = 7), (b = 7, c = 5)

Possibility 1 (b = 3, c = 5)

integer is now 253354253354

the distinct even factors = 2, 202, 262, 1934, 19802, 26462, 195334, 253354, 2000002, 2594062, 19148534, 25588754, 262000262, 1934001934, 2508457954, 253354253354

number of distinct even factors = 16

Possibility 2 (b = 5, c = 3)

integer is now 255334255334

the distinct even factors = 2, 86, 202, 5938, 8686, 19802, 253354, 599738, 851486, 2000002, 25788734, 58792138, 25588754, 86000086, 2528061934, 1934001934, 5938005938, 253354253354

number of distinct even factors = 18

Possibility 3 (b = 3, c = 7)

integer is now 253374253374

the distinct even factors = 2, 6, 22, 66, 202, 242, 606, 698, 726, 2094, 2222, 6666, 7678, 19802, 23034, 24442, 59406, 70498, 73326, 84458, 211494, 217822, 253374, 653466, 775478, 2000002, 2326434, 2396042, 6000006, 6910898, 7188126, 8530258, 20732694, 22000022, 25590774, 66000066, 76019878, 228059634, 242000242, 698000698, 726000726, 836218658, 2094002094, 2508655974, 7678007678, 23034023034, 84458084458,253354253354

number of distinct even factors = 48

Possibility 4 (b = 7, c = 3)

integer is now 257334257334

the distinct even factors = 2, 6, 14, 22, 42, 66, 154, 202, 462, 606, 1114, 1414, 2222, 3342, 4242, 6666, 7798, 12254, 15554, 19802, 23394, 36762, 46662, 59406, 85778, 112514, 138614, 217822, 257334, 337542, 415842, 653466, 787598, 1237654, 1524754, 2000002, 2362794, 3712962, 4574262, 6000006, 8663578, 11029714, 14000014, 22000022, 25990734, 33089142, 42000042, 66000066, 77207998, 121326854, 154000154, 231623994, 363980562, 462000462, 849287978, 1114001114, 2547863934, 3342003342, 7798007798, 12254012254, 23394023394, 36762036762, 85778085778, 257334257334

number of distinct even factors = 64

Possibility 5 (b = 5, c = 7)

integer is now 255374255374

the distinct even factors = 2, 14, 34, 58, 74, 202, 238, 406, 518, 986, 1258, 1414, 2146, 3434, 5858, 6902, 7474, 8806, 15022, 19802, 24038, 36482, 41006, 52318, 99586, 127058, 138614, 216746, 255374, 336634, 574258, 697102, 732674, 889406, 1517222, 2000002, 2356438, 3684682, 4019806, 5128718, 9762386, 12455458, 14000014, 21247546, 25792774, 34000034, 58000058, 68336702, 74000074, 87188206, 148732822, 238000238, 361208282, 406000406, 518000518, 986000986, 1258001258, 2146002146, 2528457974, 6902006902, 8806008806, 15022015022, 36482036482, 255374255374

number of distinct even factors = 64

Possibility 6 (b = 7, c = 5)

integer is now 257354257354

the distinct even factors = 2, 202, 19802, 257354, 2000002, 25992754, 2548061954, 257354257354

number of distinct even factors = 8

From the six possibilities, the highest number of likely distinct even factors is 64

7 0
4 years ago
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