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Inessa05 [86]
3 years ago
7

In how many ways can a six-question true-false exam be answered? (Assume that no questions are omitted.)

Mathematics
1 answer:
kap26 [50]3 years ago
8 0

Answer:

64 ways.

Step-by-step explanation:

We are asked to find the number of ways in which a six-question true-false exam be answered.

For each question there are two possible choices that are either true or false.

We have 2 options for all 6 questions.

Total number of ways: 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2=2^6=64

Therefore, there are 64 ways, in which a six-question true-false exam be answered.

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HELP PLS DUE TOMORROW WILL GIVE BRAINLIEST
Scilla [17]

Answer:

SSS: LM = AB and MN = AC

HL: AC = MN

Step-by-step explanation:

✔️Information that is necessary to prove that both triangles are congruent by SSS are:

LM = AB

MN = AC

This will is because all three corresponding sides must be congruent to each other to satisfy the SSS Congruence criterion.

✔️Information necessary to prove that the triangles are congruent by HL:

We already know that one of the corresponding legs are congruent to each either. The additional information necessary to satisfy the HL Congruence criterion is to know the hypotenuse length of each which must be congruent to each other. This, information necessary would be:

AC = MN

5 0
3 years ago
ray buys a sweatshirt from model’s for $38. he also wants to buy socks ,s, that cost $3 per pair. how many pairs of socks,s, can
SCORPION-xisa [38]

Answer:

12 pairs of socks

Step-by-step explanation:

74-38=36

36÷3=12

You subtract 38 from 74 to find out how much money he has left after buying the sweatshirt. You then divide that number by 3 to figure out how many pairs of socks he can buy with the money he has left.

8 0
3 years ago
How may minutes is 40% of 2 hours
8090 [49]
Well, we know that 1 hour is 60 minutes which means 2 hours is 120.
so to find the answer we turn 40% into a decimal which would be .40

Take .40 and multiply that by 120.
.40 * 120 is 48

40% of 2 hours is 48 minutes.

Hope this helps!

3 0
3 years ago
Read 2 more answers
Heyy! i’ll give brainliest help asap pls
NARA [144]

Answer: the answer is B

Step-by-step explanation:

5 0
3 years ago
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Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
Helga [31]

Answer:

\sum^\infty_{n=0} -5 (\frac{x+2}{2})^n

Step-by-step explanation:

Rn(x) →0

f(x) = 10/x

a = -2

Taylor series for the function <em>f </em>at the number a is:

f(x) =  \sum^\infty_{n=0} \frac{f^{(n)}(a)}{n!} (x - a)^n

f(x) = f(a) + \frac{f'(a)}{1!}(x-a)+\frac{f"(a)}{2!} (x-a)^2 + ... ............ equation (1)

Now we will find the function <em>f </em> and all derivatives of the function <em>f</em> at a = -2

f(x) = 10/x            f(-2) = 10/-2

f'(x) = -10/x²         f'(-2) = -10/(-2)²

f"(x) = -10.2/x³      f"(-2) = -10.2/(-2)³

f"'(x) = -10.2.3/x⁴     f'"(-2) = -10.2.3/(-2)⁴

f""(x) = -10.2.3.4/x⁵    f""(-2) = -10.2.3.4/(-2)⁵

∴ The Taylor series for the function <em>f</em> at a = -4 means that we substitute the value of each function into equation (1)

So, we get \sum^\infty_{n=0} - \frac{10(x+2)^n}{2^{n+1}} Or \sum^\infty_{n=0} -5 (\frac{x+2}{2})^n

4 0
3 years ago
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