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s2008m [1.1K]
3 years ago
9

If you know the density and volume of a substance, how could you find its mass?

Mathematics
1 answer:
stealth61 [152]3 years ago
4 0
Since D=MV, we can infer that M=D/V
That is your equation----------------^
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How Many Solutions?<br> 3x - 7 = 3(x - 3) + 2<br> No Solution<br> One Solution<br> Infinite Solution
prisoha [69]

Answer:

Infinite Solutions

Step-by-step explanation:

3x-7=3x(x-3)+2

3x-7=3x-9+2 - Distributive Property

3x-7=3x-7 - adding the right side together

3 0
3 years ago
Plez help with math!!
ruslelena [56]
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8 0
3 years ago
what is the value of y for the line that has a slope of 1 and goes through the points (-4,y) and(-2,8)​
kozerog [31]

Answer:

<h2>y = 6</h2>

Step-by-step explanation:

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the slope m = 1 and the points (-4, y) and (-2, 8). Substitute:

1=\dfrac{8-y}{-2-(-4)}

1=\dfrac{8-y}{2}         <em>multiply both sides by 2</em>

2=8-y         <em>subtract 8 from both sides</em>

-6=-y          <em>change the signs</em>

6=y\to y=6

7 0
3 years ago
If DEF=GJH, find each missing measure
Bas_tet [7]

Congruent triangles have equal corresponding sides and angles.

  • The measure of the side lengths are: \mathbf{DF = 16m}, \mathbf{JH = 14m} and \mathbf{GJ = 19m}
  • The measure of the angles are: \mathbf{\angle G = 34^o}, \mathbf{\angle J = 41^o} and \mathbf{\angle F = 105^o}

The given parameters are:

\mathbf{\triangle D EF \cong \triangle GJH}

\mathbf{EF = 14m}

\mathbf{D E = 19m}

\mathbf{GH = 16m}

\mathbf{\angle D = 34^o}

\mathbf{\angle H = 105^o}

\mathbf{\triangle D EF \cong \triangle GJH} means that triangles DEF and GHJ are congruent triangles.

So, we have:

\mathbf{DF = GH}

This gives

\mathbf{DF = 16m}

Also, we have:

\mathbf{JH = EF}

This gives

\mathbf{JH = 14m}

Also, we have:

\mathbf{GJ = DE}

This gives

\mathbf{GJ = 19m}

The following angles are also congruent

\mathbf{\angle F = \angle H}

This gives

\mathbf{\angle F = 105^o}

Also, we have:

\mathbf{\angle G = \angle D}

This gives

\mathbf{\angle G = 34^o}

The measure of angle J is then calculated using

\mathbf{\angle J + \angle H + \angle G = 180^o}

This gives

\mathbf{\angle J + 105 + 34= 180^o}

\mathbf{\angle J + 139= 180^o}

Subtract 139 from both sides

\mathbf{\angle J = 41^o}

Read more about congruent triangles at:

brainly.com/question/4364353

6 0
3 years ago
Pleas answer this question now in two minutes
Evgen [1.6K]

Answer:

CDB and HGI

Step-by-step explanation:

Alternate Exterior Angles are a pair of angles on the outer side of each of those two lines but on opposite sides of the transversal.

5 0
3 years ago
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