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harkovskaia [24]
3 years ago
13

I need help please

Mathematics
1 answer:
GREYUIT [131]3 years ago
5 0

Answer:

Distance = 5 units

Step-by-step explanation:

The given problem asks us to determine the distance between two points, (1, 5) and (5, 2).

<h2>Solution:</h2>

In order to find the distance between two points, we can use the following distance formula:

\displaystyle\mathsf{Distance\:(D)= \sqrt{(x_2\:-x_1)^2\:+\:(y_2\:-y_1)^2}}

Let (x₁, y₁) =   (1, 5)

     (x₂, y₂) =  (5, 2)

Step 1: Substitute points into the formula:  

\displaystyle\mathsf{Distance\:(D)= \sqrt{(x_2\:-x_1)^2\:+\:(y_2\:-y_1)^2}}

\displaystyle\mathsf{Distance\:(D)= \sqrt{(5\:-1)^2\:+\:(2\:-5)^2}}

Step 2: Subtract the integers in each of the parenthesis under the radical:

\displaystyle\mathsf{Distance\:(D)= \sqrt{(4)^2\:+\:(-3)^2}}

Step 3: Evaluate the powers (exponents):

\displaystyle\mathsf{Distance\:(D)= \sqrt{16\:+\:9}}

Step 4: Add 16 and 9:

\displaystyle\mathsf{Distance\:(D)= \sqrt{25}}

Step 5: Take the square root of 25:

⇒   Distance (D) = 5 units.

<h2>Final Answer:</h2>

Therefore, the distance between points (1, 5) and (5, 2) is <u>5 units</u>.

<h3>________________________</h3>

<u><em>Keywords:</em></u>

Distance formula

Two points

____________________________

Learn more about about this topic here:

brainly.com/question/17119550

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Anettt [7]

Answer:

Perimeter = 14 + 7\sqrt{2}

Step-by-step explanation:

Given:

Area of the square = 49 in²

Required

Determine the perimeter of the one of the congruent triangles

First, we'll determine the length of the square;

Area = Length * Length

Substitute 49 for Area

49 = Length * Length

49 = Length^2

Take Square root of both sides

7 = Length

Length = 7

<em>When the square is divided into two equal triangles through the diameter;</em>

<em>2 sides of the square remains and the diagonal of the square forms the hypotenuse of the triangle;</em>

Calculating the diagonal, we have;

Hypotenuse^2 = Length^2 + Length^2 -- Pythagoras Theorem

Hypotenuse^2 = 7^2 + 7^2

Hypotenuse^2 = 2(7^2)

Take square root of both sides

Hypotenuse = \sqrt{2} * \sqrt{7^2}

Hypotenuse = \sqrt{2} * 7

Hypotenuse = 7\sqrt{2}

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Perimeter = 7 + 7 + 7\sqrt{2}

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7 0
4 years ago
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