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allsm [11]
3 years ago
15

Why does the base of an exponent have to be greater then 1

Mathematics
1 answer:
Darina [25.2K]3 years ago
7 0

It's not 1 that is exactly the problem. It is also 0. And perhaps - 1 although that is a lot trickier than the other two.

Let's start with one. It give 1^1 = 1 for a power of 1. It gives 1^2 = 1 * 1 for a power of 2. It will give 1^100000 = 1 for a power of 100000.

So the base can be 1 but it is known that any power won't change it's value.

The same can be said of 0. 0^1000 = 0^1 = 0. 0^0 is really a bad dude. You won't learn about that for awhile.

(-1)^11 is different from (-1)^10. The first gives -1 and the second gives 1. So you have to be careful with -1.

There is nothing wrong with (1/4)^3. The power of three and the base of 1/4 are fine. The answer is (1/4)*(1/4) * (1/4) = 1/64 which is perfectly good answer.

It works for negatives too. (-1/2)^3 = - 1/8

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Answer:

x=-4 y=-1

Step-by-step explanation:

Let's solve your system by substitution.

−3x−8y=20;y=5x+19

Rewrite equations:

y=5x+19;−3x−8y=20

Step: Solve y=5x+19for y:

y=5x+19

Step: Substitute5x+19foryin−3x−8y=20:

−3x−8y=20

−3x−8(5x+19)=20

−43x−152=20(Simplify both sides of the equation)

−43x−152+152=20+152(Add 152 to both sides)

−43x=172

−43x

−43

=

172

−43

(Divide both sides by -43)

x=−4

Step: Substitute−4forxiny=5x+19:

y=5x+19

y=(5)(−4)+19

y=−1(Simplify both sides of the equation)

Answer:

x=−4 and y=−1

 

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