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3 years ago

6

Which ordered pair (c, d) is the solution to the given system of linear equations?

2 answers:

olga2289 [7]3 years ago

4 0

Answer:

a

Step-by-step explanation:

i got it right on edge

sasho [114]3 years ago

3 0

Answer:

(-1,6)

Step-by-step explanation:

The missing part of this question is the system given as;

$-c+2d=13$

$-9c-4d=-15$

We solve for c in the top equation to get:

$c=2d-13$

Substitute $c=2d-13$ into the bottom equation to get:

$-9(2d-13)-4d=-15$

Expand to get:

$-18d+117-4d=-15$

Group similar terms to get:

$-18d-4d=-15-117$

$-22d=-132$

$d=6$

Put $d=6$ into $c=2d-13$ to get:

$c=2*6-13$

$c=12-13=-1$

The solution is (-1,6)

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1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera

Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

$SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}$

$SP \approx 8.246$

$PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}$

$PA \approx 8.246$

$AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}$

$AZ \approx 8.246$

$ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}$

$ZS \approx 8.246$

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

$m_{SA} = \frac{6-(-4)}{6-(-4)}$

$m_{SA} = 1$

$m_{PZ} = \frac{4-(-2)}{-2-4}$

$m_{PZ} = -1$

Since $m_{SA}\cdot m_{PZ} = -1$ , diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

$M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)$

$M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)$

$M_{SA} = (-2,-2)+(3,3)$

$M_{SA} = (1,1)$

$M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)$

$M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)$

$M_{PZ} = (2,-1)+(-1,2)$

$M_{PZ} = (1,1)$

Then, the diagonals SA and PZ bisect each other.

8 0

2 years ago

Solve the equation

Zina [86]

Answer: the equivalent equation is found by distributing the 1/4 to get 4+3x=28

the first step is subtract 4 to both sides

the second step is divide both sides by 3

the answer is x=8

Step-by-step explanation:

3 0

2 years ago

Help, please <br> no links

oksano4ka [1.4K]

Answer: A

Step-by-step explanation:

1/3n (variable)

-3 (it says subtracted)

(is less than 6)

(n is less that 27)

7 0

3 years ago

A suit is on sale for 29% off. the sale price is $568. what is the regular price?

Eduardwww [97]

569.65...assuming that your rounding up.

I forgot to move the decimal 4 spaces.

to get the answer multiply 568.00
X .29
_________
1.6472

round 1.647 to 1.65 then add that to 568.00

3 0

3 years ago

Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!

andriy [413]

Answer:

44.1

Step-by-step explanation:

Cosine = Adjacent over Hypotenuse

Adjacent of ∠T = 28 and hypotenuse = 39

Which means that $cos(x)=\frac{28}{39}$

Now we solve for x

To get rid of the "cos" we take the inverse of cos ( which is $cos^-^1$ ) and apply it to each side

$cos^-^1((cos)x) = x\\cos^-^1(\frac{28}{39} )=44.11461855$

We're left with x = 44.11461855

Our last step is to round to the nearest tenth and we get that the answer is 44.1

3 0

2 years ago