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Alja [10]
3 years ago
8

The original sale price of an item at markdowns is $110.95. You have an additional 20% off coupon for markdowns for purchases to

taling $90.00 or more. Using the coupon, how much more do save when compared to the original sale price?
Mathematics
2 answers:
zvonat [6]3 years ago
7 0

Answer:

You will save $22.19 when compared to the original sale price.

Step-by-step explanation:

The original sale price of an item at markdowns is $110.95.

You have an additional 20% off coupon for markdowns for purchases totaling $90.00 or more.

So, this becomes:

0.20\times110.95=22.19 dollars

Hence, you will save $22.19 when compared to the original sale price.

IRINA_888 [86]3 years ago
5 0

Answer:

$22.19

Step-by-step explanation:

20% off the original price = $110.95 - (20% x $110.95)

20% x $110.95 = $22.19

$110.95 - $22.19 = $88.76

difference = $110.95 - $88.76 = $22.19

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Answer:

42.22% probability that the weight is between 31 and 35 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 34.6, \sigma = 2.8

What is the probability that the weight is between 31 and 35 pounds

This is the pvalue of Z when X = 35 subtracted by the pvalue of Z when X = 31. So

X = 35

Z = \frac{X - \mu}{\sigma}

Z = \frac{35 - 34.6}{2.8}

Z = 0.14

Z = 0.14 has a pvalue of 0.5557

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42.22% probability that the weight is between 31 and 35 pounds

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