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Nesterboy [21]
3 years ago
9

PLEASE HELP!! WILL GIVE BRAINLIEST IF UR RIGHT!!

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
3 0
<span>ratio of the surface area of the sphere to the surface area of the cube
=
</span>4nr^2 / <span>24r^2 = n/6

answer

</span><span>A.
n/6</span>
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-4(-6 - 2n) = 30 + 8n
kati45 [8]

Answer:

n=6/4

Step-by-step explanation:

-4(-6-2n)=30+8n

24+12n=30+8n

-24       =-24

12n=6+8n

-8n =   -8n

4n=6

n=6/4

8 0
2 years ago
The equation 9y-6x=36 is written in standard form. What is the first step when writing an equivalent equation which solves for x
defon
The answer is D. Subtract 9y from both sides of the equation. 
7 0
3 years ago
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Is the additive inverse of an integer always negative? Explain.
andre [41]

Answer:

Step-by-step explanation:

We do not consider zero to be a positive or negative number. For each positive integer, there is a negative integer, and these integers are called opposites. For example, -3 is the opposite of 3, -21 is the opposite of 21, and 8 is the opposite of -8. ... If an integer is less than zero, we say that its sign is negative

3 0
3 years ago
Can somebody step by step explain how to solve this problem??<br><br> (3x^2y)(-7xy^3)
charle [14.2K]

Answer:

\boxed{\bold{-21x^3y^4}}

Explanation:

[ Step One ] Remove Parenthesis: (a) = a

\bold{-3x^2y\cdot \:7xy^3}

[ Step Two ] Multiply: \bold{3\cdot \:7=21}

\bold{-21x^2xy^3y}

[ Step Three ] Apply Exponent Rule \bold{\:a^b\cdot \:a^c=a^{b+c}: \ x^2x=\:x^{2+1}=\:x^3}

\bold{-21x^3y^3y}

[ Step Four ] Apply Exponent Rule: \bold{y^3y=\:y^{1+3}=\:y^4}

\bold{-21x^3y^4}

[ \boxed{\bold{Final \ Answer}} ]

➤ \bold{-21x^3y^4}

\boxed{\bold{Mordancy}}

5 0
3 years ago
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What is 6.685 rounded to the nearest hundredths place
loris [4]

Answer:

6.69

Step-by-step explanation:

The hundredths place is two decimal places to the right. This lands you at 8, so you must look at the number after it to determine whether you round up or down. So you look at 5, which rounds the 8 up to 9. Therefore, it is 6.69

7 0
3 years ago
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