Answer:
90.67% probability that John finds less than 7 golden sheets of paper
Step-by-step explanation:
For each container, there are only two possible outcomes. Either it contains a golden sheet of paper, or it does not. The probability of a container containing a golden sheet of paper is independent of other containers. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper containers.
This means that
14 of these containers of paper.
This means that
What is the probability that John finds less than 7 golden sheets of paper?
In which
90.67% probability that John finds less than 7 golden sheets of paper
The answer to this question is 120
Yes because when your multiply every thing together you’ll have 9/15 miles
Answer:
Each student gets 2 1/3
Step-by-step explanation:
So you would divide 7 by 3, which you can't...so 6 divided by 3 is 2, and when you split the last one into thirds you can each have 1/3. Add the sections together, and each person gets 2 1/3
To solve for proportion we make use of the z statistic.
The procedure is to solve for the value of the z score and then locate for the
proportion using the standard distribution tables. The formula for z score is:
z = (X – μ) / σ
where X is the sample value, μ is the mean value and σ is
the standard deviation
when X = 70
z1 = (70 – 100) / 15 = -2
Using the standard distribution tables, proportion is P1
= 0.0228
when X = 130
z2 = (130 – 100) /15 = 2
Using the standard distribution tables, proportion is P2
= 0.9772
Therefore the proportion between X of 70 and 130 is:
P (70<X<130) = P2 – P1
P (70<X<130) = 0.9772 - 0.0228
P (70<X<130) = 0.9544
Therefore 0.9544 or 95.44% of the test takers scored
between 70 and 130.