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shutvik [7]
2 years ago
10

\s\sqrt{x} 8-2\sqrt[n]{x} 12\\

Mathematics
1 answer:
mixer [17]2 years ago
7 0

Answer: =8s\sqrt{x}-24\sqrt[n]{x}

Step-by-step explanation:

s\sqrt{x}\cdot \:8-2\sqrt[n]{x}\cdot \:12

=8s\sqrt{x}-24\sqrt[n]{x}

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21g-6f-8g
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3 years ago
Plz help ASAP thanks
m_a_m_a [10]

Answer:

No because the line does not pass through the origin

Step-by-step explanation:

to be proportional it has to go through the origin

7 0
3 years ago
Read 2 more answers
1) Which diagram shows the correct construction of a line parallel to line l and passing through point P?
kherson [118]

1)To construct a line parallel to line l and passing through point P our first step is to join the point and line and then draw angles in such a way so that corresponding angles are equal.

Option B is the correct construction of a line parallel to line l and passing through point P.

2) To Construct the perpendicular line to line DE at point F we cut an arc from point F  to line DE in such a way it cuts line DE at two points .From these two points we draw arcs which cut each other .

Option C is the correct option  to Construct the perpendicular line to line DE at point F.

3) To Construct a perpendicular from the given line segment that passes through the given point we cut two arcs on top and bottom of line segment.

Option B is the right answer.

3 0
3 years ago
What is x?
Dvinal [7]

Answer:

x= 3/17

Step-by-step explanation:

4x(2x+6) =8x^2(23-5)

8x^2 +24x = 144 x^2

24x = 136 x^2

24= 136 x

x=24/136

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4 0
2 years ago
let n be a natural number such that GCF(n, 70)= 10, and LCM(n, 70)=210. Find N. (Hint: Do you remember that LCM(A,B) x GCF(A, B)
Luden [163]

The natural number , n is 30

<h3>How to determine the value</h3>

Given;

GCF(n, 70) = 10

LCM(n, 70) = 210

We have that;

LCM(A,B) x GCF(A, B)= A x B

Then,

(n, 70) = n × 70 = 70n

10 × 210 = 2100

Equate the two expressions

70n = 2100

n = \frac{2100}{70}

n = 30

Thus, the natural number , n is 30

Learn more about GCF and LCM here:

brainly.com/question/640517

#SPJ1

4 0
2 years ago
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