If I’m correct, I think A. 0.3x2 is the correct answer.
B=3 i believe but not positive
Y - y₁ = m(x - x₁)
y - 3 = -6(x - 0)
y - 3 = -6(x) + 6(0)
y - 3 = -6x + 0
+ 3 + 3
y = -6x + 3
Question: 6^x = 1 (finding x)
Answer: x = 0
Explanation: Any non-zero expression raised to the power of 0 equals 1. Since we are trying to find 1, 0 would be an appropriate vale for x.
