these inequalities can be solved just like equations
a. x - 7 > 25
+ 7 +7 x > 32the number line would have a filled in circle at 32 with an arrow pointing to the rightb. x - 8 < 5+8 +8x < 13 the number line would have an empty circle at 13 with an arrow pointing to the leftc.x + 11 > 23 - 11 - 11x > 12the number line would have an empty circle at 12 with an arrow pointing to the rightd. x + 12 < 6 - 12 - 12 x < -6the number line would have a filled in circle at -6 with an arrow pointing to the lefta. 21 < x + 18 -18 -18 3 < xx > 3b. 16 < x - 7 + 7 + 7 23 < x x > 23c. 12 > x - 7 + 7 + 7 19 > x x < 19d. 29 < x + 53 - 53 - 53 -24 < x x > -24e. 15 > x + 19 -19 -19 -4 > x x < -4f. 35 > x - 8 +8 +8 43 > x x < 43g. -6 < x - 18 +18 +18 12 < x x > 12h. -15 < x - 2 + 2 +2 -13 < x x > -13
<u><em>Answer:</em></u>
<u><em>y = 50</em></u>
<u><em>Step-by-step explanation:</em></u>
<u><em>Since 20 is even with 100, all we have to do is multiply both sides by 5.</em></u>
<u><em>(5 × 20%) × y = 10 × 5</em></u>
<u><em>y = 50</em></u>
<u><em>Please give me brainliest :)</em></u>
Answer:C
Step-by-step explanation:
To solve these problems, you usually have a favor the numerator. For example, on #7, label your terms, 1 from m^2 is A, -6m from -6 is B and your constant, 8, is C. Next you have to find out what two numbers can be multiplied to give you for C term but can also add together to give you your B term. For this specific problem, -4 and -2 gives you 8 and also adds to be -6. After that, you put your -4 and -2 into their own separate parentheses along with the M from M^2. It should look this like: (m-4)(m-2)/(m-2). Now you notice that the binomial on the bottom and one of the binomials on top is the exact same, so you would cancel that out and your answer would be (m-4).
90 because there are 5 time as many candies with nuts as candies without nuts and there is 18 so it will be 18×5=90
