6/10
300/500
30/50
60/100
12/20
1+3+5+7+...+999 =
= 1+2+3+4+...+500
+1+2+3+...+499
= 2·(1+2+3+...+499) + 500
= 2·(499·500)/2 + 500
= 499·500 + 500
= 500·(499 + 1)
= 500·500
= 250.000
Tan x =opposite/ adjacent =9/5
x= arctan(9/5)≈61
Answer:
d = 11.401754
For:
(X1, Y1) = (5, 4)
(X2, Y2) = (-4, -3)
Distance Equation Solution:
=√ (-4−5)2+(−3−4)2
=√ (-9)2+(−7)2
=√ 81+49
=√ 130
=11.401754
Answer:
(r + 20)t = r
Step-by-step explanation:
Distance is constant in the scenario above, distance from home to wedding and wedding back home is the same.
From wedding back home. :
Recall : Distance = speed * time
Distance = r * 1 hour
From home to wedding :
Speed = 20 mph more ; r + 20
Time = t
Distance = (r + 20)* t = (r +20)t
Since the distance are the same, we can equate both :
(r + 20)t = r * 1
= (r + 20)t = r
