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Anna35 [415]
4 years ago
14

Ingrid and Bobby work as secretaries. Over the last six hours, Ingrid typed a 4,500 word document, a 9,000 word document, and a

6,750 word document. Bobby took five hours to type a 1,750 word document and a 14,000 word document. Together, how many words did they type per minute?
Mathematics
2 answers:
timama [110]4 years ago
7 0

Answer:

54

Step-by-step explanation:

*Ingrid*

Total words are 4500+900+6750=20250 words

Rate per hour will be 20250÷6=3375 words per hour

*Bobby*

Total words will be 1750+14000=15750

Rate per hour will be 15750÷5=3150 words per hour

Average rate per hour will be

(3375+3150)/2=3262.5 worda per hour

Rate per minute will be 3262.5÷60=54.375 words per minute

Rounded off, this is approximately 54 words per minute

miskamm [114]4 years ago
3 0

Answer:

60 words per minute

Step-by-step explanation:

Ingrid typed following number of words in 6 hours:

4,500 word document, a 9,000 word document, and a 6,750 word document.

So, the total number of words that Ingrid typed in 6 hours = 4500 + 9000 + 6750 = 20250 words

Bobby typed following number of words in 5 hours:

1,750 word document and a 14,000 word document.

So, the total number of words that Bobby typed in 5 hours = 1750 + 14000 = 15750 words.

In total both Ingrid and Bobby took 5 + 6 = 11 hours to type 20250 + 15750 = 36000 words

We have to find how many words did they type per minute. Lets convert, 11 hours to minutes first.

1 hour = 60 minutes

So,

11 hours = 11 x 60 = 660 minutes

Ingrid and Bobby typed 36000 words in 660 minutes. dividing 36000 by 660 will give us the number of words they both typed per minute.

So, the number of words they both typed per minutes = \frac{36000}{660}=60 words per minute

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Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe
nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let D^c be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that  one person in 10,000 people has a rare genetic disease.

So,P(D)=\frac{1}{10000}

Only 0.4% of the people who don't have it test positive.

P(A|D^c) = probability that a person is tested positive given he don't have a disease = 0.004

P(D^c)=1-\frac{1}{10000}

Formula:P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}

P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}

P(D|A)=\frac{2470}{2471}=0.9995

P(D|A)=0.9995

A)The probability that someone who tests positive has the disease is 0.9995

(B)

P(D^c|A^c)=probability that someone does not have disease given that he tests negative

P(A^c|D^c)=probability that a person tests negative given that he does not have disease =1-0.004

=0.996

P(A^c|D)=probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}

P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}

P(D^c|A^c)=0.99999

B)The probability that someone who tests negative does not have the disease is 0.99999

8 0
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If y=2x+10 and X= -2 then what is y
lara [203]
Y=2•(-2)+10
Y=-4+10
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8 0
3 years ago
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Lady_Fox [76]

Answer:

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Step-by-step explanation:

Given that,

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ATQ,

Total students = males + females

40 = x+6+x

40-6 = 2x

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Hence, there are 17 females and (6+17= 23) males.

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skelet666 [1.2K]
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Now to get the speed in meters per second we divide the total meters run by the total seconds
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The degenerate conic that is formed when a double cone is sliced at the ap-ex by a plane parallel to the base of the cone is a <u>Point</u>.

<h3>What degenerate conic is formed?</h3>

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Circles lead to a Point degenerate conic being formed because a single point will be formed on the double cone that separates the shape.

Find out more on degenerate conics at brainly.com/question/14276568

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