X+Y=10
XY=-300
Solve for one of the variables
X=10-Y
Plug into the other equation
Y(10-Y)=-300
Now, you have a quadratic...
-y²-10y+300=0
I would multiply everything by -1, so there's no coefficient on y²
y²+10y-300=0
And solve...
-10±√(100-4(-300))
----------------------------
2
Y=-5±5√(13)
Plug back onto original equation...
X+(-5±5√(13))=10
X±5√(13)=15
X=15±5√(13)
Note: There are 2 sets of answers, keep the negatives with the negatives, and the positives with the positives when dealing with the ±.
Complete the square since can't factor
2/2=1
add 1 to both sides
x²+2x+1-6=1
factor perfect square
(x+1)²-6=1
add 6 to both sides
(x+1)²=7
sqrt both sides
x+1=+/-√7
minus 1 both sides
x=-1+/-√7
so x=-1+√7 or x=-1-√7
Jeremy has 24 and ria has 40 if there is anything u need to ask how that was foung as
29 = 13 + 4x
16 = 4x
x = 4
The number is 4
Answer:
x = 10
Step-by-step explanation:
25x + 10 = 260
=> 25x = 250
=> x = 10
Hoped this helped.
