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3 years ago

10

The point (x, y) is the top of a polygon. Which point would it map to if the polygon were reflected over the y-axis and then tra

nslated 6 units down?

1 answer:

snow_lady [41]3 years ago

3 0

You would have to add

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Find the domain of

ch4aika [34]

Answer:

C (x ≥ -6)

Step-by-step explanation:

<u>Algebraic:</u>

The domain of $\sqrt{x}$ is $x\geq 0$ . When transformed 6 units to the left, it becomes $x\geq -6$

<u>Graphically:</u>

As shown in the attached graph, $x\geq -6$ .

6 0

3 years ago

Help me plz branniest to whoever right

Iteru [2.4K]

Answer:

vertex: (-1,25)

aos; -1

left x int: -6

right x int: 4

(not sure)

range is less than of equal to 25

4 0

2 years ago

Which sampling would be appropriate to survey 120,000 people?

kipiarov [429]

Answer: Id say b

Step-by-step explanation: a would be too high and a bit too detailed. Whereas c and d will be inaccurate.

8 0

3 years ago

Solve each equation and check to make sure both solutions work<br> 2|5x-3|+10=4

Ede4ka [16]

If your just looking for x then x=2

7 0

3 years ago

Given right triangle ABCABC with altitude \overline{BD} BD drawn to hypotenuse ACAC. If BC=10BC=10 and DC=5,DC=5, what is the le

Helen [10]

Answer: $\overline{AC}=$ 12.5

Step-by-step explanation: The triangle ABC and its altitude $\overline{BD}$ is represented in the figure below.

<u>Altitude</u> is a segment of line that link a vertex and the opposite side, forming a right angle.

So, because of $\overline{BD}$ , now we have two similar triangles, which means that ratios of corresponding sides are equal:

$\frac{\overline{BD}}{\overline{BC}} =\frac{\overline{AD}}{\overline{BD}}$

$\overline{BD}^{2}=\overline{BC}.\overline{AD}$ (1)

This is always true for a right triangle and a altitude drawn to the hypotenuse.

Triangle BDC is also right triangle. So, we can use Pythagorean theorem to determine the missing side.

$\overline{BC}^{2}=\overline{CD}^{2}+\overline{BD}^{2}$

$\overline{BD}^{2}=\overline{BC}^{2}-\overline{CD}^{2}$ (2)

Substituting (2) into (1):

$\overline{BC}^{2}-\overline{CD}^{2}=\overline{BC}.\overline{AD}$

We want to find f, so:

$\overline{AD}=\frac{\overline{BC}^{2}-\overline{CD}^{2}}{\overline{BC}}$

$f=\frac{10^{2}-5^{2}}{10}$

f = 7.5

The length of $\overline{AC}$ is

$\overline{AC}=f+5$

$\overline{AC}=7.5+5$

$\overline{AC}=12.5$

The length of the hypotenuse of triangle ABC is 12.5 units.

5 0

2 years ago

Read 2 more answers