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4 years ago

10

An account compounds interest, at a rate of 9%, once a year. Emily puts $1000 in the account as the principal. Create a function

to track the amount of money she has.

1 answer:

wariber [46]4 years ago

6 0

Your answer would be 1090 because the formula is 1000(1+.09/1)^1

You might be interested in

a small business has an average income of 3000 per month with a standard deviation of 250. if the income in a given month is 330

Vika [28.1K]

Answer:

<u>The correct answer is z = 1.2</u>

Step-by-step explanation:

μ or average income = US$ 3,000

σ or standard deviation = US$ 250

Income in a given month = US$ 3,300

For calculating the z score, we use the following formula:

z = (x – μ) / σ

z = (3,300 – 3,000 / 250)

z = 300/250

z = 6/5 = 1.2

Interpreting z

A Z score tells us how many units of standard deviation (1.2 in this case)from the average a given score is, that is, we do not count in quantity of points, but in quantities of standard deviations. To use the Z score we require the distribution to be normal and to know the average and standard deviation of the scores.

8 0

3 years ago

Solve and explain how you did

Sliva [168]

Answer:

We conclude that:

$-\left(9x\right)^0=-1$

Step-by-step explanation:

Given:

$-\left(9x\right)^0$

To determine:

Explain how to solve the expression

<u>Solving the expression</u>

$-\left(9x\right)^0$

Apply the exponent rule

$a^0=1,\:\quad \:a\ne \:0$

so the expression becomes

$-\left(9x\right)^0\:=\:-1$

Therefore, we conclude that:

$-\left(9x\right)^0=-1$

4 0

3 years ago

Dan buys a car for £2700.

BartSMP [9]

Answer:

The car will be worth £2516.22 in 5 years

Step-by-step explanation:

The rule of depreciating is

$A=P(1-r)^{t}$ , where

<em>A</em> is the new value

<em>P</em> is the original value

<em>r</em> is the rate in decimal

<em>t</em> is the time in years

∵ Dan buys a car for £2700

∴ <em>P</em> = 2700

∵ It depreciates at a rate of 1.4% per year

∴ <em>r</em> = 1.4% = 1.4/100 = 0.014

∵ We need to find how much it will be worth in 5 years

∴ <em>t</em> = 5

→ Substitute all of these values in the rule above to find A

∵ $A=2700(1-0.014)^{5}$

→ Use your calculator to find the answer

∴ <em>A</em> = 2516.22

∴ The car will be worth £2516.22 in 5 years

7 0

3 years ago

A hypothesis test is conducted with a significance level of 10%. The alternative hypothesis states that more than 15% of a popul

Drupady [299]

Answer:

D. We cannot conclude that more than 15% of the population has at least one sibling.

Step-by-step explanation:

Data given and notation

n represent the random sample taken

X represent the number of people who has at least one sibling

$\hat p$ estimated proportion of people who has at least one sibling

$p_o=0.15$ is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of people who has at least one sibling is more than 0.15:

Null hypothesis: $p\leq 0.15$

Alternative hypothesis: $p > 0.15$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Let's assume that the calculated value for this case is $z_{calc}$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z> z_{calc})=0.27$

So the p value obtained was a very high value and using the significance level given $\alpha=0.1$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 10% of significance the proportion of people who has at least one sibling is not significanlty higher than 0.15.

So then the best answer for this case would be:

D. We cannot conclude that more than 15% of the population has at least one sibling.

6 0

3 years ago

HELP PLS I DONT KNOW THESE STUFF AND THIS SCHOOL KEEP GIVING IT TO ME SOOO

choli [55]

What’s the question

8 0

3 years ago

Read 2 more answers