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Artyom0805 [142]
4 years ago
5

Which equation would define a graph that has its vertex on (2, 0) and opens to the right?

Mathematics
1 answer:
Fed [463]4 years ago
8 0
I guess the equation would be y^2 = 4(x-2)

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Consider the table of values and the equation, which both represent a function,
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Answer:

y = 5x - 2

Step-by-step explanation:

✅Rate of change = change in y/change in x

Rate of change of the table of values using two pairs of values from the table (2, 8) and (3, 11):

Rate of change = (11 - 8)/(3 - 2) = 3/1

Rate of change = 3

✅Rate of change of the equation, y = 5x - 2.

The equation is represented in the slope-intercept form, y = mx + b.

Where, m = slope/rate of change

Therefore, rate of change if the equation would be 5.

Rate of change = 5

✔️The function that has the greater rate of change would therefore be y = 5x - 2

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