<span>x – 2z = 9 so x = 2z + 9
6x – 2y – 5z = 29
–5x + 5y + 3z = –14
substitute </span>x = 2z + 9 into 6x – 2y – 5z = 29 and –5x + 5y + 3z = –14
6(2z + 9) – 2y – 5z = 29
12z + 54 - 2y -5z =29
-2y + 7z = - 25 (1st equation)
–5(2z + 9) + 5y + 3z = –14
-10z - 45 + 5y + 3z = -14
5y - 7z = 31 (2nd equation)
multiply (1st) equation by 5 and (2nd) equation by 2
-10y + 35z = - 125
10y - 14z = 62
-----------------------add
21z = - 63
z = -3
substitute z = - 3 into x = 2z + 9
x = 2z + 9
x = 2(-3) + 9
x = 3
substitute x = 3 and z = 3 into <span>6x – 2y – 5z = 29
</span>
<span>6x – 2y – 5z = 29
</span><span>6(3) – 2y – 5(-3) = 29
18 - 2y + 15 = 29
-2y + 33 = 29
-2y = -4
y = 2
x = 3, y = 2 and z = -3
answer
</span><span>B. (3, 2, –3)</span>
Answer:
Can you show a picture? Or like tell us the options?
Answer:
$4000
Step-by-step explanation:
Assuming a = money invested at 9%
Assuming b = money invested at 8%
then we can form am equation from the question given
1) a + b = $10000, also
0.09a + 0.08b = $860 -> multiply by 100
2) 9a + 8b = $86000
Next we try to solve both equations simultaneously. We multiply both the left hand side and the right hand side of the first equation by 8. We have
3) 8a + 8b = $80000, now we subtract 3 from 2
9a + 8b = $86000
-8a - 8b = -$80000
a = $6000.
Then, we plug this in any of the first 2 equations, to get b
9 * $6000 + 8b = $86000
$54000 + 8b = $86000
8b = $86000 - $54000
8b = $32000
b = $32000/8
b = $4000.
Therefore, he invested $4000 at 8%
To answer this question you need to know the conversion rate from kilometer into cm. For every kilometer it would be 1000m and for 1m it will be 100cm. That mean 1km is equal to 100,000cm or 10^5 cm. Then the answer would be:
(3.34 * 10^5 cm) * (1km/10^5cm)= 3.34km