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scoundrel [369]
3 years ago
13

which rule would apply to the expression w^2w^3. A.addition rule. B.power rule. C.distributive rule. D.quotient to difference ru

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Mathematics
1 answer:
Free_Kalibri [48]3 years ago
4 0
"Power rule" is the one rule among the following choices given in the question that <span>would apply to the expression w^2w^3. The correct option among all the options that are given in the question is the second option or option "B". I hope that this is the answer that has actually come to your desired help.</span>
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Use the method of undetermined coefficients to find the general solution to the de y′′−3y′ 2y=ex e2x e−x
djverab [1.8K]

I'll assume the ODE is

y'' - 3y' + 2y = e^x + e^{2x} + e^{-x}

Solve the homogeneous ODE,

y'' - 3y' + 2y = 0

The characteristic equation

r^2 - 3r + 2 = (r - 1) (r - 2) = 0

has roots at r=1 and r=2. Then the characteristic solution is

y = C_1 e^x + C_2 e^{2x}

For nonhomogeneous ODE (1),

y'' - 3y' + 2y = e^x

consider the ansatz particular solution

y = axe^x \implies y' = a(x+1) e^x \implies y'' = a(x+2) e^x

Substituting this into (1) gives

a(x+2) e^x - 3 a (x+1) e^x + 2ax e^x = e^x \implies a = -1

For the nonhomogeneous ODE (2),

y'' - 3y' + 2y = e^{2x}

take the ansatz

y = bxe^{2x} \implies y' = b(2x+1) e^{2x} \implies y'' = b(4x+4) e^{2x}

Substitute (2) into the ODE to get

b(4x+4) e^{2x} - 3b(2x+1)e^{2x} + 2bxe^{2x} = e^{2x} \implies b=1

Lastly, for the nonhomogeneous ODE (3)

y'' - 3y' + 2y = e^{-x}

take the ansatz

y = ce^{-x} \implies y' = -ce^{-x} \implies y'' = ce^{-x}

and solve for c.

ce^{-x} + 3ce^{-x} + 2ce^{-x} = e^{-x} \implies c = \dfrac16

Then the general solution to the ODE is

\boxed{y = C_1 e^x + C_2 e^{2x} - xe^x + xe^{2x} + \dfrac16 e^{-x}}

6 0
1 year ago
A lion runs at a speed of 50 mph and a cheetah runs 78 mph. If they both run at a steady rate, how far will a cheetah run in the
Elden [556K]

Answer:

21.45 mi

Step-by-step explanation:

Distance = speed × time

The time it takes the lion is:

13.75 mi = 50 mi/hr × t

t = 0.275 hr

The distance ran by the cheetah in that time is:

d = 78 mi/hr × 0.275 hr

d = 21.45 mi

7 0
3 years ago
Read 2 more answers
Can someone help me with this
Naya [18.7K]

Answer:

the answer should be 8.9

you square 12 and square the 8 and subtract them by each other

3 0
3 years ago
Read 2 more answers
Morris has 2 3/4 gallons of ice tea. He gives 3/7 of it to her friend. How many gallons of ice tea does Morris have left?
lara31 [8.8K]

Answer:

2 \frac{9}{28} gallons of ice tea is left with Morris

Step-by-step explanation:

Morris has 2 3/4 gallons of ice tea. He gives 3/7 of it to her friend.

Morris has 2 3/4 gallons of ice tea

2\frac{3}{4}= \frac{2*4+3}{4}=\frac{11}{4}

He gives 3/7 of it to her friend.

To find how many gallons of ice tea does Morris have left , we subtract 3/7 from 11/4

\frac{11}{4}- \frac{3}{7}

Make the denominators same

\frac{11*7}{4*7}- \frac{3*4}{7*4}

\frac{77}{28}- \frac{12}{28}

\frac{65}{28}

\frac{65}{28} = 2 \frac{9}{28}

7 0
3 years ago
Yo help me out please.​
katrin2010 [14]

Answer:

12

Step-by-step explanation:

-12 = -3/4x + 3

-9 = -3/4x

-9 = (-3/4) times x

-9 = (-3/4) times 12

hope this helps! :)

6 0
3 years ago
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