Answer:
Step-by-step explanation:
Given that you have eight cards. Five are green and three are yellow. The five green cards are numbered 1, 2, 3, 4, and 5. The three yellow cards are numbered 1, 2, and 3. The cards are well shuffled. You randomly draw one card.
G = card drawn is green
Y = card drawn is yellow
E = card drawn is even-numbered
List:
Sample space = {G1, G2, G3, G4, G5, Y1, Y2, Y3}
2) P(G) = 5/8
3) P(G/E) = P(GE)/P(E)
GE = {G2, G4}
Hence P(G/E) = 2/5
4) GE = {G2, G4}
P(GE) = 2/8 = 1/4
5) P(G or E) = P(G)+P(E)-P(GE)
= 5/8 + 3/8-2/8 = 3/5
6) No there is common element as G2 and G4
Cannot be mutually exclusive
-6 (negative six) is the answer
Answer:
Step-by-step explanation:
We have been given two expressions 
and
Now we need to find out least common multiple of these two expressions.
First we need to find out what is common factor of both expressions. and
Least common multiple means find the expression which can be divided by both expressions.
15 and 6 both goes into 30
so 30 is part of LCM (least common multiple )
Now pickup the highest exponent of each variable.
So we get 
Hence required least common multiple is
Answer:
6x+1
Step-by-step explanation:
Answer:
there are fourteen 4-point questions and twenty six 2-point questions.
Step-by-step explanation:
Given : A 40-question test has 108 possible points.
There are m 4-point questions and n 2-point questions.
So , equation for total number of questions in the test :
m + n = 40 | 4n + 2n = 108
Multiplying (i) by 2 , we get
2m + 2n = 80
Subtract (iii) from (ii) , we get
2m = 28
⇒ m = 28/ 2 = 14
Using value of m in (i) , we get
14 + n = 40 ⇒ n = 26
from this we get there are fourteen 4-point questions and twenty six 2-point questions.
hope this helped!
