Answer:
उत्तर:
गोलाको आयतन :4851 cm³
⁴/3 πr³=4851
r³=4851×3×7/(22*4)
r³=1157.625
r=![\sqrt[3]{1157.625}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B1157.625%7D%20)
r=10.5
अब
गोलाको व्यास=2×r=10.5*2=21cm.
Answer:
Since,
Length is 4 times Breadth
Let Breadth be x
Therefore,Length=4x
Perimeter=50m
Therefore,
50m=2(l+b)
50m=2(4x+x)
50m=2(5x)
50m=10x
x=5m.
Therefore,
Breadth=5m
Length=4x=4×5=20m
Answer:
You are definitely correct! It is 81w^2.
Step-by-step explanation:
Remember
a/b times c/d=(ac)/(bd)
also remember add exponents with similar bases when mutiplying
x^m times x^n=x^(m+n)
(x^4)/3 times (x^2)/3=(x^4 times x^2)/(3*3)=(x^(4+2))/9=(x^6)/9
answer is (x^6)/9
Answer:
Step-by-step explanation:
Given a set of data sorted from smallest to largest, i.e. arranged in ascending order we are to find out the median, I and III quartiles
We know that the median is the middle entry of data arranged in ascending order
Q1 is the entry below which 25% lie and Q3 is one above which 25% lie
Hence proper definition would be
d. The first quartile is the median of the lower half of the data below the overall median.
The second quartile is the overall median
The third quartile is the median of the upper half of the data above the overall median.
Option b is wrong becuase mean is not necessary here. Option a is wrong because this has nothing to do with std deviation
Option c is wrong since minimum value cannot be q1
Option e is wrong because we have exactly 25% lie below Q1
