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Harman [31]
4 years ago
10

In the diagram shown, line m is parallel to line n. Cruz says that ∠4 and ∠6 are congruent angles. Is he correct? Why or why not

?

Mathematics
2 answers:
Stolb23 [73]4 years ago
8 0

Answer:

(B) {\angle}4 and {\angle}7 are congruent corresponding angles and  {\angle}7 and {\angle}6 are vertical angles.

Step-by-step explanation:

It is given that line m is parallel to line n.

Now, {\angle}4 is congruent to {\angle}7 because they are corresponding angles which are always congruent.

Also, {\angle}7 is congruent to {\angle}6, because they form vertically opposite angle pair, thus

{\angle}4 will be congruent to {\angle}6.

Hence, Cruz is correct that {\angle}4 is congruent to {\angle}6 because {\angle}4 and {\angle}7 are congruent corresponding angles and  {\angle}7 and {\angle}6 are vertical angles.

Therefore, option B is correct.

kozerog [31]4 years ago
7 0
The answer is the upper 2nd choice to the right :)

Please mark as brainliest, if you found this helpful.
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The weekly amount of money spent on maintenance and repairs by a company was observed, over a long period of time, to be approxi
VikaD [51]

Answer:

$512.90 should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with mean $480 and standard deviation $20.

This means that \mu = 480, \sigma = 20

How much should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05?

This is the 100 - 5 = 95th percentile, which is X when Z has a pvalue of 0.95, so X when Z = 1.645.

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 480}{20}

X - 480 = 1.645*20

X = 512.9

$512.90 should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05

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Step-by-step explanation:

___________________

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3 years ago
Which is the simplified form of this expression? <br><br> (2x+3) (x-6)-2x^2+3x+30
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-6x + 12

To find this answer, follow these steps:

First, multiply 2x + 3 and x - 6 using either the FOIL method or the box method. This should get you the answer of 2x^2 - 9x - 18

This should now replace the 2x + 3 and x - 6

So with that, you should have this currently:

2x^2 - 9x - 18 - 2x^2 + 3x + 30

Now, combine like terms:

The 2x^2 cancels each other out. After that, combine -9x and 3x to get -6x. Then -18 and 30.

This should leave you with the final answer of -6x + 12

Hope this helps!
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